Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
2014
2016
2017
2018
Answer: Option
Explanation:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year    : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1    2    1    1    1    2    1    1    1    2    1    

Sum = 14 odd days 0 odd days.

Calendar for the year 2018 will be the same as for the year 2007.

Discussion:
121 comments Page 9 of 13.

Rupali said:   1 decade ago
Why we are not considered 2018? Answer please.

KATY said:   1 decade ago
X/4 (x=given year).

For any year divided by 4, the possibility of remainders are 0, 1, 2, 3.

If remainder is 0---->x+28.

If remainder is 1---->x+6.

If remainder is 2 (or) 3------>x+11.

So 2007 divide by 4 gives 3 as remainder.

So 2007+11 = 2018.

Rya said:   1 decade ago
Please explain clearly how that 14 odd days is equivalent to 0 days?

Gopi said:   1 decade ago
Please explain about 2018 why we are not considering 2018? Please explain quickly very urgent.

Shreyas D.J. said:   1 decade ago
The addition is coming 14 odd days = 0 odd days for year 2017 not 2018.

So why take 2018 if it has 1 odd day?

Amol Jadhav said:   1 decade ago
@Prabhuchandu.

Can you explain why you add years with 28, 6, 11, 11..and all?

Chandu said:   1 decade ago
How can you tell that we should add 6, 11, 28? Can you explain it.

Jenny said:   1 decade ago
Why we want to find the odd numbers only from 2007 to 2017. Why we not find the odd numbers 2018?

Sundar GS said:   1 decade ago
@Prabhuchandu.

Can you explain why you add years with 6, 11, 28...and all?

Prabhuchandu said:   1 decade ago
Easy method: 2000+28 = 2028.
2001+6 = 2007.
2002+11 = 2013.
2003+11 = 2015.
2004+28 = 2032.
2005+6 = 2011.
2006+11 = 2017.
2007+11 = 2018.


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