Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 8 of 13.
Niks said:
8 years ago
Thank you for easy method @Prabhuchandu.
Krishna kittu said:
8 years ago
For finding repeated calendars we used formulae of adding 28, 6, 11. for finding the past repeated calendars we have to subtract same 28, 6, 11. Am I right?
Riya khandelwal said:
8 years ago
I am not understanding this.
Please explain how 2018 will be similar to 2007?
Please explain how 2018 will be similar to 2007?
Siri said:
8 years ago
Whenever they ask for the same calender we should check whether it is a leap year or not. If it is a leap year add 28 to the given year then you will get the same calendar for leap year for non- leap years. 6 and 11 (6 is added when given year is subtracted from previous leap year u shoud get 1.
i.e ex=2005 is not a leap year..previous leap year is 2004 so (04-05=1), then add 6 because we got 1 after subtracting non-leap year with previous leap year so (2005+6=2011).
(11 is added when you subtract non-leap year to previous leap year you will get 2 nor 3).
Ex:2006 is a non-leap year, previous leap yr is 2004 so(04-06=2).
i.e 2006+11=2017.
i.e ex=2005 is not a leap year..previous leap year is 2004 so (04-05=1), then add 6 because we got 1 after subtracting non-leap year with previous leap year so (2005+6=2011).
(11 is added when you subtract non-leap year to previous leap year you will get 2 nor 3).
Ex:2006 is a non-leap year, previous leap yr is 2004 so(04-06=2).
i.e 2006+11=2017.
Aishwarya said:
8 years ago
The number of extra days more than a complete week in a given period is called odd days.
Hence there are 14 days which can be of 2 weeks.
As 7 days is one week and other 7 days are another week so there are no more days which are beyond a complete week.
Therefore, the odd days are 0.
Hence there are 14 days which can be of 2 weeks.
As 7 days is one week and other 7 days are another week so there are no more days which are beyond a complete week.
Therefore, the odd days are 0.
Sowmya said:
8 years ago
Is this procedure is same for leap year? Please, anyone explain.
Balu Srinivas Reddy said:
8 years ago
For 4n => add 28 years.
If 2004
Will same in 2004+28=2032
For 4n+1 => add 6 years.
4n+2 & 4n+3 - add 11 years.
If 2004
Will same in 2004+28=2032
For 4n+1 => add 6 years.
4n+2 & 4n+3 - add 11 years.
Vijay said:
8 years ago
Please explain in detail.
Anu said:
8 years ago
It applies to all years:
Leap year == add 28.
1 yr after leap year== add 6.
2 yr after leap year== add 11.
3 yr after leap year == add 11.
Here 2007, nearest leap year before 2007, 2004. Therefore 2007 is 3 yrs after 2004. Therefore add 11 to 2007=2017.
Leap year == add 28.
1 yr after leap year== add 6.
2 yr after leap year== add 11.
3 yr after leap year == add 11.
Here 2007, nearest leap year before 2007, 2004. Therefore 2007 is 3 yrs after 2004. Therefore add 11 to 2007=2017.
Manjunath N said:
8 years ago
Assume 2007 starts with Sunday.
2008 starts - monday.
Since 2008 is leap year hence
2009 starts - wednesday.
2010 starts - thursday.
2011 starts- friday.
2012 starts-sat.
2012 is leap year
2013 starts- monday.
2014 starts - tuesday.
2015 starts- wednesday.
2016 starts- thursday.
2016 is leap year
2017 starts- saturday.
2018 starts - sunday
Hence 2018 will have same year as 2017.
2008 starts - monday.
Since 2008 is leap year hence
2009 starts - wednesday.
2010 starts - thursday.
2011 starts- friday.
2012 starts-sat.
2012 is leap year
2013 starts- monday.
2014 starts - tuesday.
2015 starts- wednesday.
2016 starts- thursday.
2016 is leap year
2017 starts- saturday.
2018 starts - sunday
Hence 2018 will have same year as 2017.
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