Aptitude - Calendar - Discussion

Thanks for the explanation.

I have a small doubt. As per your method for calendar 1988 year the calendar should be repeated on 1992. But it is repeated on 2016. How it is possible? Please explain.

Simply divide 14 by 7 if zero remainder so odd day zero.

2007 is a normal year and front year 2006 is also a normal year then we have to add 11years to the given year.

i.e; 2007 + 11years = 2018.

It's for the upcoming years. How to calculate the same year backward?

Please tell me the solution for this problem.

If, 24march 1992 is Friday then which day fall on 24september 1993?

It is so simple to calculate , no need to find Jan 1, 2007.

If the year is completely divisible with 4,

i.e remainder = 0 then simply add 23 years to the question year.
remainder = 1 then simply add 6 years to the question date,
remainder = 2 or 3 then simply add 11 years to the question.

Example:

Which year is same as;

2004 ? answer : 2004 + 23 = 2027.
2005 ? 2005 + 6 = 2011.
2006 ? 2006 + 11= 2017.
2007 ? 2007 + 11 =2018.

2004, 2008, 2012............ +23.
2005, 2009, 2013..............+ 6.
2006, 2010, 2014..............+11.
2007,2011, 2015...............+11.

Is there any mistakes excuse me.

If you get a equal calendar for x year= (x + 11) year. Because equal calender's obtain in every after 11 year.

To find that the year is a leap year or an ordinary year. The year should be divided by 4 if you get the remainder as 0 then it must be a leap year or else if you get a remainder as 1 or 2 or 3 then it must be a ordinary year. Hope you understand.

It is as same as 400th year (leap year) can any one differenciate it?

How can we decide that the year is an ordinary year and leap year? Please help me.