Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 4 of 13.
Sheetal said:
7 years ago
In these types of questions, divide last 2digits of the given year from 4, after that if divisible is--
2 and 3 add 11in it,
1 add 6 in it,
0 add 28 in it.
Eg.2007(07/4) divisible is 3 so add 11 in 2007= 2018.
2 and 3 add 11in it,
1 add 6 in it,
0 add 28 in it.
Eg.2007(07/4) divisible is 3 so add 11 in 2007= 2018.
Mithilesh Mahatha said:
4 years ago
@All.
So, doubt here is how 14 = 0,
See,
No of days in a week is 7.
In 14 we can make to weeks,
14/7 completely divides no remainder.
Therefore 0 odd days.
All multiple of 7 will gives 0 odd days..
So, doubt here is how 14 = 0,
See,
No of days in a week is 7.
In 14 we can make to weeks,
14/7 completely divides no remainder.
Therefore 0 odd days.
All multiple of 7 will gives 0 odd days..
(2)
Pavan kumar said:
9 years ago
Thanks for the explanation.
I have a small doubt. As per your method for calendar 1988 year the calendar should be repeated on 1992. But it is repeated on 2016. How it is possible? Please explain.
I have a small doubt. As per your method for calendar 1988 year the calendar should be repeated on 1992. But it is repeated on 2016. How it is possible? Please explain.
Shahir said:
1 decade ago
We are supposed to find the day of the week on a given date.
For this, we use the concept of 'odd days'.
In a given period, the number of days more than the complete weeks are called odd days.
For this, we use the concept of 'odd days'.
In a given period, the number of days more than the complete weeks are called odd days.
Paveek said:
10 years ago
@Hariharan.
2018 is not included because upto 2017 it is 14 so the next year is repeated year.
We just need perfect week (7, 14, 21....) next year of the perfect week is the repeated year.
2018 is not included because upto 2017 it is 14 so the next year is repeated year.
We just need perfect week (7, 14, 21....) next year of the perfect week is the repeated year.
Rakesh Parmar said:
9 years ago
@All, Simply remember this.
Divide Any year by 4.
If you get 0, add 28 to given year,
Ex. 2000+28 = 2028.
2000 and 2008 both same year.
If you get 1 add + 6.
If you get 2 or 3 add + 11.
Divide Any year by 4.
If you get 0, add 28 to given year,
Ex. 2000+28 = 2028.
2000 and 2008 both same year.
If you get 1 add + 6.
If you get 2 or 3 add + 11.
Riya said:
2 years ago
@All.
Why won't 2014 be considered as its sum be 21 odd days then 21/3 = remainder being 0 or 2014 - 2007.
So 7yrs + 0 odd day.
=>7/ 7 = 0
Hence 2014 could also be the same year? right?
Why won't 2014 be considered as its sum be 21 odd days then 21/3 = remainder being 0 or 2014 - 2007.
So 7yrs + 0 odd day.
=>7/ 7 = 0
Hence 2014 could also be the same year? right?
(14)
Santhosh said:
9 years ago
I have a query regarding the year 2006.
No of odd days for respective years.
1, 1, 2, 1, 1, 1.
Till 2011, total odd days becomes 0 hence answer should be 2011 but it is 2017 why?
No of odd days for respective years.
1, 1, 2, 1, 1, 1.
Till 2011, total odd days becomes 0 hence answer should be 2011 but it is 2017 why?
Santhosh said:
9 years ago
I have a query regarding the year 2006.
No of odd days for respective years.
1, 1, 2, 1, 1, 1.
Till 2011, total odd days becomes 0 hence answer should be 2011 but it is 2017 why?
No of odd days for respective years.
1, 1, 2, 1, 1, 1.
Till 2011, total odd days becomes 0 hence answer should be 2011 but it is 2017 why?
Santhosh said:
9 years ago
I have a query regarding the year 2006.
No of odd days for respective years.
1, 1, 2, 1, 1, 1.
Till 2011, total odd days becomes 0 hence answer should be 2011 but it is 2017 why?
No of odd days for respective years.
1, 1, 2, 1, 1, 1.
Till 2011, total odd days becomes 0 hence answer should be 2011 but it is 2017 why?
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