Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 4 of 13.
Akanksha said:
7 years ago
Why do we take till 2017? Please explain.
Jitendra said:
7 years ago
2007 last two digit division by 4.
if the remainder is 1, add 6. remainder is 2 add 11, and 3 add 11 get an answer.
if the remainder is 1, add 6. remainder is 2 add 11, and 3 add 11 get an answer.
Evlin said:
7 years ago
Good one @Katy. It's a time efficient method. Thanks.
Vinod said:
7 years ago
Nice, Thanks @Prasand.
Rupa said:
7 years ago
Why this trick is not applicable to 2008. Can anyone explain?
Shivam giri said:
7 years ago
The calendar of 1872 repeated on which year and why?
Please explain the answer.
Please explain the answer.
Dfeverx said:
7 years ago
For every ordinary year number of odd days = 1 odd day.
For leap year number of odd days = 2 odd days.
2016-2 (sum=2)
2017-1 (sum=3)
2018-1 (sum= 4)
2019-1 (sum=5)
2020-2 (sum=7)
It implies next year i.e 2021 will have the same calendar as 2016.
For leap year number of odd days = 2 odd days.
2016-2 (sum=2)
2017-1 (sum=3)
2018-1 (sum= 4)
2019-1 (sum=5)
2020-2 (sum=7)
It implies next year i.e 2021 will have the same calendar as 2016.
Jitendra Singh said:
8 years ago
Calander of 2016 is repeated in which year? Please explain.
Prudhviraj said:
8 years ago
@ALL.
start with following year
2008 ->2
09 ->1
10 ->1
11 ->1
12 ->2
-------
sum= 7 is divisible by 7 (no option for 2012)
--------
13 ->1
14 ->1
15 ->1
16 ->2
17 ->1
18 ->1
-------
sum= 7 is divisible by 7 ( option D for 2018 )
-------
start with following year
2008 ->2
09 ->1
10 ->1
11 ->1
12 ->2
-------
sum= 7 is divisible by 7 (no option for 2012)
--------
13 ->1
14 ->1
15 ->1
16 ->2
17 ->1
18 ->1
-------
sum= 7 is divisible by 7 ( option D for 2018 )
-------
Sharayu said:
8 years ago
How is the odd days for year 2017 1? I still didn't get this?
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