Aptitude - Calendar - Discussion

I have query regarding year 2002.

Years- 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013.

No of odd days for respective years.

1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2.

Till 2007 total odd days becomes 0 hence answer should be 2008 but it is 2013 why ?

The year 2002 calender and the year 2007 have the same calender.

@ sandy.

Will you tell me the calculation behind that ?

Wow prasad! nice.

Please briefly explain this problem.

Please tell us how to findout a day when date, month, year are given.

@anand ques is to find a year whose calender wil b same as 2007
so you should go for coming years where the sum of odd days will be multiples of 7(which makes exact week)
for a regular year we wil be having 365/7 which gives remainder 1 will be having 1 odd day
and for leap years we will be havin 2 odd days
YEAR ODD DAYS
2007 1
2008(LEAP) 2
2009 1
2010 1
2011 1
2012(LEAP) 2
2013 1
2014 1
2015 1
2016(LEAP) 2
2017 1
here we will get the sum of odd days as 14 which again makes exact 2 weeks...so next year will get the same calender of 2007

The calender for the year 2008 will be the same for the year.

Guys calender will be same if their number of odd days will be same
2007..6*1+2=8,1 odd day.

2014-3 odd days.

2017-0 odd days.

2018-1 days. So answer will be 2018.

As in formulas we heard that for 1990 = 1600+300 => 0+1 => 1(odd day) => is that sunday or monday?