Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 2 of 13.
T Prashanth said:
1 year ago
2008-2 odd days-leap year.
2009-1 odd days.
2010-1 odd days.
2011-1 odd days.
2012-2 odd days-leap year.
2013-1 odd days.
2014-1 odd days.
2015-1odd days.
2016-2 odd days - leap year
2017-1 odd days.
2018-1 odd days.
Up to total odd days 14,
So 1 week = 7days
so 14/7 = 0.
The zero comes 14th odd day of the 2018 year
So the answer is 2018.
Here, 2012 also get sum = 7
So 1 week = 7 days,
So 7/7=0.
2009-1 odd days.
2010-1 odd days.
2011-1 odd days.
2012-2 odd days-leap year.
2013-1 odd days.
2014-1 odd days.
2015-1odd days.
2016-2 odd days - leap year
2017-1 odd days.
2018-1 odd days.
Up to total odd days 14,
So 1 week = 7days
so 14/7 = 0.
The zero comes 14th odd day of the 2018 year
So the answer is 2018.
Here, 2012 also get sum = 7
So 1 week = 7 days,
So 7/7=0.
(12)
Ravi Maurya said:
3 years ago
This solution is not correct.
Rule:- 1.
If there are 2 leap years in 5 normal years then we can observe the same date and day.
Rule:- 2.
If there is not 2 leap years in 5 normal years then there is 1 leap year in 6 years then we can observe the same date and day.
Rule:-3.
If there is not even 1 leap year in 5 years and 6 years, then we can celebrate the same date and day after 11 years.
Rule:- 1.
If there are 2 leap years in 5 normal years then we can observe the same date and day.
Rule:- 2.
If there is not 2 leap years in 5 normal years then there is 1 leap year in 6 years then we can observe the same date and day.
Rule:-3.
If there is not even 1 leap year in 5 years and 6 years, then we can celebrate the same date and day after 11 years.
(6)
Manjunath N said:
8 years ago
Assume 2007 starts with Sunday.
2008 starts - monday.
Since 2008 is leap year hence
2009 starts - wednesday.
2010 starts - thursday.
2011 starts- friday.
2012 starts-sat.
2012 is leap year
2013 starts- monday.
2014 starts - tuesday.
2015 starts- wednesday.
2016 starts- thursday.
2016 is leap year
2017 starts- saturday.
2018 starts - sunday
Hence 2018 will have same year as 2017.
2008 starts - monday.
Since 2008 is leap year hence
2009 starts - wednesday.
2010 starts - thursday.
2011 starts- friday.
2012 starts-sat.
2012 is leap year
2013 starts- monday.
2014 starts - tuesday.
2015 starts- wednesday.
2016 starts- thursday.
2016 is leap year
2017 starts- saturday.
2018 starts - sunday
Hence 2018 will have same year as 2017.
Gireesh kumar said:
5 years ago
@Kunal.
See, what is the remainder after dividing the year by 4. If the remainder is 1 add 5 years to the given year. If the remainder is 2 add 11 to the given year. If the remainder is 3 adding 11 to the given year. So in the above question, they gave 2007. After dividing by 4. It gives the remainder as 3. So simply add 11 years to 2007. That will be 2018.
Hope it helps you.
See, what is the remainder after dividing the year by 4. If the remainder is 1 add 5 years to the given year. If the remainder is 2 add 11 to the given year. If the remainder is 3 adding 11 to the given year. So in the above question, they gave 2007. After dividing by 4. It gives the remainder as 3. So simply add 11 years to 2007. That will be 2018.
Hope it helps you.
(5)
Manish said:
6 years ago
2007 is a general year so either it will repeat after year or 11 year let's see;
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017.
Odd day : 1 1 2 1 1 1 2 1 1 1 2 .
If the addition is 7 then the calendar will change but 2012 is leap year so general year can't be a leap year so now we go till the 14.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017.
Odd day : 1 1 2 1 1 1 2 1 1 1 2 .
If the addition is 7 then the calendar will change but 2012 is leap year so general year can't be a leap year so now we go till the 14.
Meghana said:
5 years ago
Ordinary year = 1odd day.
Leap year = 2odd days.
They told to fïnd oud same calendar as 2007, so we should start counting an odd day from 2008,
2008-2odd day
2009-1odd day
2010-1odd day
2011-1odd day
2012-2odd day
Add the above odd days. To get same calendar odd days should be multiple of 7. 7 divided by 7 gives reminder 0. Hence 2012 is the answer.
Leap year = 2odd days.
They told to fïnd oud same calendar as 2007, so we should start counting an odd day from 2008,
2008-2odd day
2009-1odd day
2010-1odd day
2011-1odd day
2012-2odd day
Add the above odd days. To get same calendar odd days should be multiple of 7. 7 divided by 7 gives reminder 0. Hence 2012 is the answer.
Prudhviraj said:
8 years ago
@ALL.
start with following year
2008 ->2
09 ->1
10 ->1
11 ->1
12 ->2
-------
sum= 7 is divisible by 7 (no option for 2012)
--------
13 ->1
14 ->1
15 ->1
16 ->2
17 ->1
18 ->1
-------
sum= 7 is divisible by 7 ( option D for 2018 )
-------
start with following year
2008 ->2
09 ->1
10 ->1
11 ->1
12 ->2
-------
sum= 7 is divisible by 7 (no option for 2012)
--------
13 ->1
14 ->1
15 ->1
16 ->2
17 ->1
18 ->1
-------
sum= 7 is divisible by 7 ( option D for 2018 )
-------
Mandakranta said:
6 years ago
2009 was repeated in 2015.
2009 - 1 odd day
2010 - 1 (2)
2011 - 1 (3)
2012 - 2 (5)
2013 - 1 (6)
2014 - 1 (7)
So 2015 is the answer.
Again 2009 being non-leap year if we divide by 4 we get a remainder 1. So 2009 + 11= 2020 which is not possible 2020 being a leap year. So 2009 +6 =2015 is the repeated the year of 2009.
2009 - 1 odd day
2010 - 1 (2)
2011 - 1 (3)
2012 - 2 (5)
2013 - 1 (6)
2014 - 1 (7)
So 2015 is the answer.
Again 2009 being non-leap year if we divide by 4 we get a remainder 1. So 2009 + 11= 2020 which is not possible 2020 being a leap year. So 2009 +6 =2015 is the repeated the year of 2009.
(1)
Sundar said:
2 decades ago
Hi Friends,
Please go through the basics terms and formulas given below before solving the problems.
Link: http://www.indiabix.com/aptitude/calendar/formulas
Hope this will help you to solve the problems in this section.
Please go through the basics terms and formulas given below before solving the problems.
Link: http://www.indiabix.com/aptitude/calendar/formulas
Hope this will help you to solve the problems in this section.
Aishwarya said:
8 years ago
The number of extra days more than a complete week in a given period is called odd days.
Hence there are 14 days which can be of 2 weeks.
As 7 days is one week and other 7 days are another week so there are no more days which are beyond a complete week.
Therefore, the odd days are 0.
Hence there are 14 days which can be of 2 weeks.
As 7 days is one week and other 7 days are another week so there are no more days which are beyond a complete week.
Therefore, the odd days are 0.
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