Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 12 of 13.
Sheetal said:
7 years ago
In these types of questions, divide last 2digits of the given year from 4, after that if divisible is--
2 and 3 add 11in it,
1 add 6 in it,
0 add 28 in it.
Eg.2007(07/4) divisible is 3 so add 11 in 2007= 2018.
2 and 3 add 11in it,
1 add 6 in it,
0 add 28 in it.
Eg.2007(07/4) divisible is 3 so add 11 in 2007= 2018.
Manish said:
6 years ago
2007 is a general year so either it will repeat after year or 11 year let's see;
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017.
Odd day : 1 1 2 1 1 1 2 1 1 1 2 .
If the addition is 7 then the calendar will change but 2012 is leap year so general year can't be a leap year so now we go till the 14.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017.
Odd day : 1 1 2 1 1 1 2 1 1 1 2 .
If the addition is 7 then the calendar will change but 2012 is leap year so general year can't be a leap year so now we go till the 14.
Pradyumna Kumar Tiwari said:
6 years ago
If the year is leap then add 28 to get the same calendar provided that no century year which does not leap should fall in between.
If the year is not leap, add 11 and if the result is not leap; the result has the same calender. If the result is leap then add 6 to get same calender. It should be taken that no century year which is not leap should not fall in between.
2007 is not leap so 2007+11=2018, 2018 is not leap; hence 2018 is the answer.
If the year is not leap, add 11 and if the result is not leap; the result has the same calender. If the result is leap then add 6 to get same calender. It should be taken that no century year which is not leap should not fall in between.
2007 is not leap so 2007+11=2018, 2018 is not leap; hence 2018 is the answer.
Pradyumna Kumar Tiwari said:
6 years ago
The two necessary conditions for the same calendar is;
1) Both years must either be normal or both leap.
2) A number of odd days between two years must be 0.
1) Both years must either be normal or both leap.
2) A number of odd days between two years must be 0.
Fathima safwana said:
6 years ago
Is this Holds good for for year where for which year 2009 will be same ?
Ank said:
6 years ago
Step1- calculate odd days from given year to that year at which addition is divisible bye 7.
Meghana said:
5 years ago
Ordinary year = 1odd day.
Leap year = 2odd days.
They told to fïnd oud same calendar as 2007, so we should start counting an odd day from 2008,
2008-2odd day
2009-1odd day
2010-1odd day
2011-1odd day
2012-2odd day
Add the above odd days. To get same calendar odd days should be multiple of 7. 7 divided by 7 gives reminder 0. Hence 2012 is the answer.
Leap year = 2odd days.
They told to fïnd oud same calendar as 2007, so we should start counting an odd day from 2008,
2008-2odd day
2009-1odd day
2010-1odd day
2011-1odd day
2012-2odd day
Add the above odd days. To get same calendar odd days should be multiple of 7. 7 divided by 7 gives reminder 0. Hence 2012 is the answer.
Kunal said:
5 years ago
How the odd days taken here?
Aniket said:
5 years ago
Then, What is the solution for 2008?
Anyone explain to me.
Anyone explain to me.
Vigneshwaran said:
4 years ago
Thanks for explaining @Prasad.
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