Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 12 of 13.
Hariharan said:
1 decade ago
Hi All
Pls explain me why 2018 is not included in this step.
Pls explain me why 2018 is not included in this step.
Priya said:
1 decade ago
This calendar method will take time to find the day of the week.... I have seen a new easy method in an quantitative aptitude book BEACON....if possible read that book
Manisha said:
1 decade ago
You are right prasad
Prasad said:
1 decade ago
For every ordinary year number of odd days = 1 odd day
For leap year number of odd days = 2 odd days.
If the odd days sum=7 implies odd days=0 then again loop starts from 1,2,3,4,..7 .
2008,2012,2016 are clearly leap years,
therefore
2007=1 odd day,
2008=2 (SUM=3),
2009=1 (SUM=4),
2010=1 (SUM=5),
2011=1 (SUM=6),
2012=2 odd days (SUM=8)
[HERE OBSERVE THAT SUM OF ODD DAYS EXCEEDING THE VALUE 7 THEREFORE CONTINUE ADDING THE ODD DAYS TILL WE GET A NUMBER WHICH IS DIVISIBLE BY 7],
2013=1 (SUM=9),
2014=1 (SUM=10),
2015=1 (SUM=11),
2016 = 2 odd days (SUM=13),
2017=1 (SUM=14)
upto 2017 SUM OF ODD DAYS = 14 divisible by 7 implies next year i.e.,2018 will have same calender as 2007 .
For leap year number of odd days = 2 odd days.
If the odd days sum=7 implies odd days=0 then again loop starts from 1,2,3,4,..7 .
2008,2012,2016 are clearly leap years,
therefore
2007=1 odd day,
2008=2 (SUM=3),
2009=1 (SUM=4),
2010=1 (SUM=5),
2011=1 (SUM=6),
2012=2 odd days (SUM=8)
[HERE OBSERVE THAT SUM OF ODD DAYS EXCEEDING THE VALUE 7 THEREFORE CONTINUE ADDING THE ODD DAYS TILL WE GET A NUMBER WHICH IS DIVISIBLE BY 7],
2013=1 (SUM=9),
2014=1 (SUM=10),
2015=1 (SUM=11),
2016 = 2 odd days (SUM=13),
2017=1 (SUM=14)
upto 2017 SUM OF ODD DAYS = 14 divisible by 7 implies next year i.e.,2018 will have same calender as 2007 .
(3)
Nitesh Nandwana said:
1 decade ago
The number of days more than the complete weeks are called odd days.
Sundar said:
1 decade ago
Hi Friends,
Please go through the basics terms and formulas given below before solving the problems.
Link: http://www.indiabix.com/aptitude/calendar/formulas
Hope this will help you to solve the problems in this section.
Please go through the basics terms and formulas given below before solving the problems.
Link: http://www.indiabix.com/aptitude/calendar/formulas
Hope this will help you to solve the problems in this section.
Harru said:
2 decades ago
Sum = 14 odd days 0 odd days.
plz clerify this point
plz clerify this point
Mani` said:
2 decades ago
I don't have much time to wait for your explanation, It's very emergency ? so, please respond to my questions ?
Mani said:
2 decades ago
Need a brief explanation for this problem?
Mani said:
2 decades ago
How to find odd days?
and how it's possible?
and how it's possible?
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