Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 10 of 13.
Aishwarya said:
8 years ago
The number of extra days more than a complete week in a given period is called odd days.
Hence there are 14 days which can be of 2 weeks.
As 7 days is one week and other 7 days are another week so there are no more days which are beyond a complete week.
Therefore, the odd days are 0.
Hence there are 14 days which can be of 2 weeks.
As 7 days is one week and other 7 days are another week so there are no more days which are beyond a complete week.
Therefore, the odd days are 0.
Sowmya said:
8 years ago
Is this procedure is same for leap year? Please, anyone explain.
Balu Srinivas Reddy said:
8 years ago
For 4n => add 28 years.
If 2004
Will same in 2004+28=2032
For 4n+1 => add 6 years.
4n+2 & 4n+3 - add 11 years.
If 2004
Will same in 2004+28=2032
For 4n+1 => add 6 years.
4n+2 & 4n+3 - add 11 years.
Vijay said:
8 years ago
Please explain in detail.
Anu said:
8 years ago
It applies to all years:
Leap year == add 28.
1 yr after leap year== add 6.
2 yr after leap year== add 11.
3 yr after leap year == add 11.
Here 2007, nearest leap year before 2007, 2004. Therefore 2007 is 3 yrs after 2004. Therefore add 11 to 2007=2017.
Leap year == add 28.
1 yr after leap year== add 6.
2 yr after leap year== add 11.
3 yr after leap year == add 11.
Here 2007, nearest leap year before 2007, 2004. Therefore 2007 is 3 yrs after 2004. Therefore add 11 to 2007=2017.
Manjunath N said:
8 years ago
Assume 2007 starts with Sunday.
2008 starts - monday.
Since 2008 is leap year hence
2009 starts - wednesday.
2010 starts - thursday.
2011 starts- friday.
2012 starts-sat.
2012 is leap year
2013 starts- monday.
2014 starts - tuesday.
2015 starts- wednesday.
2016 starts- thursday.
2016 is leap year
2017 starts- saturday.
2018 starts - sunday
Hence 2018 will have same year as 2017.
2008 starts - monday.
Since 2008 is leap year hence
2009 starts - wednesday.
2010 starts - thursday.
2011 starts- friday.
2012 starts-sat.
2012 is leap year
2013 starts- monday.
2014 starts - tuesday.
2015 starts- wednesday.
2016 starts- thursday.
2016 is leap year
2017 starts- saturday.
2018 starts - sunday
Hence 2018 will have same year as 2017.
Pratik said:
8 years ago
How to find answer this question?
Seema remembers that her mother's birthday falls on after 21st January but before 25th January while his brother remembers that it falls after 23rd January but before 28th January. When is Seema mother birthday?
Seema remembers that her mother's birthday falls on after 21st January but before 25th January while his brother remembers that it falls after 23rd January but before 28th January. When is Seema mother birthday?
Sharayu said:
8 years ago
How is the odd days for year 2017 1? I still didn't get this?
Prudhviraj said:
8 years ago
@ALL.
start with following year
2008 ->2
09 ->1
10 ->1
11 ->1
12 ->2
-------
sum= 7 is divisible by 7 (no option for 2012)
--------
13 ->1
14 ->1
15 ->1
16 ->2
17 ->1
18 ->1
-------
sum= 7 is divisible by 7 ( option D for 2018 )
-------
start with following year
2008 ->2
09 ->1
10 ->1
11 ->1
12 ->2
-------
sum= 7 is divisible by 7 (no option for 2012)
--------
13 ->1
14 ->1
15 ->1
16 ->2
17 ->1
18 ->1
-------
sum= 7 is divisible by 7 ( option D for 2018 )
-------
Jitendra Singh said:
8 years ago
Calander of 2016 is repeated in which year? Please explain.
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