Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 15)
15.
January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
Answer: Option
Explanation:
The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.
Discussion:
45 comments Page 5 of 5.
Hassan Azizi said:
2 years ago
How it would be Tuesday?
Anyone, please explain to me.
Anyone, please explain to me.
Nitin said:
2 years ago
Correct Explanation Hear!
If the given period includes February month with leap year then only the odd day will be == 2.
Otherwise, it will be an odd day == 1.
Here, the give question,
Period = 1, JAN, 2007 To 1, JAN, 2008.
Where only one February month (Feb/2007).
And 2007 is not a leap year so it has odd day = 1.
If given range 1, Feb, 2007 to 1, Feb, 2008.
Then hear 2 February include 1. Feb 2007 and Feb 2008 so total odd day =1+2 =3.
Thank you.
If the given period includes February month with leap year then only the odd day will be == 2.
Otherwise, it will be an odd day == 1.
Here, the give question,
Period = 1, JAN, 2007 To 1, JAN, 2008.
Where only one February month (Feb/2007).
And 2007 is not a leap year so it has odd day = 1.
If given range 1, Feb, 2007 to 1, Feb, 2008.
Then hear 2 February include 1. Feb 2007 and Feb 2008 so total odd day =1+2 =3.
Thank you.
(1)
Biswajit Pal said:
1 year ago
The correct answer is Wednesday.
Because one year gap +1 plus one leap year +1= +2.
Mon + 2 = Wednesday is the right answer.
Because one year gap +1 plus one leap year +1= +2.
Mon + 2 = Wednesday is the right answer.
(4)
Hita said:
1 year ago
Is it Tuesday or Wednesday?
Anyone, please explain the right answer clearly.
Anyone, please explain the right answer clearly.
Oji khalnayak said:
2 months ago
Option B is correct because.
Leap year 2008 was not considered because 1 January was taken.
So, add +1.
Leap year 2008 was not considered because 1 January was taken.
So, add +1.
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