Aptitude - Calendar - Discussion

It will be Sunday.

As we know that calender repeats itself after every 400 years.

Doomsday's for that 400 years are.

1800 - 1899 Friday.
1900 - 1999 Wednesday.
2000 -2099 Tuesday.
2100 - 2199 Sunday.

So 1800. , 1400, 1000, 600, 200 all will have Friday as doomsday.

So 200 AD has Friday as doomsday.
100 AD has Sunday as doomsday.
0 AD has Tuesday as doomsday.

Now going forward in the intervals of 400 years from 0.

So 542695283200 AD (clearly divisible by 400) will have Tuesday as doomsday.

Now we have to calculate the doomsday of 17 th year of a century whose initial doomsday is Tuesday.

It will be similar to 2000-2099 (as 2000 has Tuesday as doomsday). So calculate the doomsday of 2017. That is Tuesday.

So 6 June of that year is Tuesday.
So clearly 25 June will be Sunday.

Since 2008 is a leap year we should not count 2 odd days because the year was not completed.

2007:1 odd day.

Monday + 1 odd day = Tuesday.

Yes, Tuesday is the right answer because in 2008 it was not crossed February. So only one odd day Monday + 1 = Tuesday.

As per my calculation Answer is Wednesday.

It should be Wednesday.

If 3rd Jan 1991 was Friday, which day must be the new year day in the year 1998?

Please answer this question.

It is Friday @Dominic.

We are having 2 leap year in between those 7 years, so (5 + 4 = 9) 2 odd days.

Therefore 3 Jan1998 is Sunday which means Jan 1 is Friday.

Which is the correct answer? please tell me.

The answer should be Wednesday.

The calendar of the year 2008 says that Jan 1 is Tuesday. And that is the right answer. I think @Suresh Reddy and @Hari are absolutely right.