Aptitude - Boats and Streams - Discussion
Discussion Forum : Boats and Streams - General Questions (Q.No. 11)
11.
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
Answer: Option
Explanation:
Rate downstream = | ![]() |
1 | x 60 | ![]() |
10 |
Rate upstream = 2 km/hr.
Speed in still water = | 1 | (6 + 2) km/hr = 4 km/hr. |
2 |
![]() |
![]() |
5 | ![]() |
1 | hrs = 1 hr 15 min. |
4 | 4 |
Discussion:
27 comments Page 3 of 3.
Sowmya said:
10 years ago
I can't understand, please help me.
Vikas said:
1 decade ago
In this, why we calculate average?
Anu said:
10 years ago
How can rate upstream be 2 km/hr?
Something said:
1 decade ago
Please tell me how to calculate ?
Abhisek said:
1 decade ago
How is downstream 6km/hr?
Manideep said:
7 years ago
Thank you @Sonia.
Varshith said:
5 years ago
Thanks @Mayur.
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