Aptitude - Boats and Streams - Discussion
Discussion Forum : Boats and Streams - General Questions (Q.No. 11)
11.
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
Answer: Option
Explanation:
Rate downstream = | ![]() |
1 | x 60 | ![]() |
10 |
Rate upstream = 2 km/hr.
Speed in still water = | 1 | (6 + 2) km/hr = 4 km/hr. |
2 |
![]() |
![]() |
5 | ![]() |
1 | hrs = 1 hr 15 min. |
4 | 4 |
Discussion:
27 comments Page 1 of 3.
Hasi said:
3 months ago
I agree that the answer will be 1 hour 25 min.
Anandh said:
3 years ago
@All.
It's very simple.
Speed of the downstream S = D/T.
D= 1km,
T = 10mint, mint convert to hour.
10/60 hour then,
S = 1km / (10/60)hr,
= 60/10 km/hr.
Downstream speed s = 6 km/hr then,
Upstream speed S = D/T.
= 2km / 1hr = 2km / hr.
Speed in still water = 1/2 ( Down S + Up S )
1/2 ( 6+2 ) = 4km / hr.
So we need T? For stationary water, D is given 5km ...
Then Speed in still water = 4km /hr.
T = D / S = 5/ 4
= 1 1/4 hours.
= 1hr 15 mint.
It's very simple.
Speed of the downstream S = D/T.
D= 1km,
T = 10mint, mint convert to hour.
10/60 hour then,
S = 1km / (10/60)hr,
= 60/10 km/hr.
Downstream speed s = 6 km/hr then,
Upstream speed S = D/T.
= 2km / 1hr = 2km / hr.
Speed in still water = 1/2 ( Down S + Up S )
1/2 ( 6+2 ) = 4km / hr.
So we need T? For stationary water, D is given 5km ...
Then Speed in still water = 4km /hr.
T = D / S = 5/ 4
= 1 1/4 hours.
= 1hr 15 mint.
(15)
ABI said:
5 years ago
@Kessy
Simply need to find the speed of the boat.
You have downstream and upstream speed and,
Downstream speed=Speed of boat +Speed of stream.
6=x+y---------> 1
Upstream speed=Speed of boat-Speed of stream
4=x-y------------> 2
Solve both 1&2 equations and get x that is the speed of the boat.
Simply need to find the speed of the boat.
You have downstream and upstream speed and,
Downstream speed=Speed of boat +Speed of stream.
6=x+y---------> 1
Upstream speed=Speed of boat-Speed of stream
4=x-y------------> 2
Solve both 1&2 equations and get x that is the speed of the boat.
(2)
Kessy said:
5 years ago
Anyone, please explain this step 1/2 times (6 + 2).
Varshith said:
5 years ago
Thanks @Mayur.
Ibrana said:
6 years ago
Please discuss the proper way to find required time.
Thomas said:
6 years ago
I also agree, The answer should be 1h and 25 mins.
(3)
Mayur said:
7 years ago
Speed = Distance /Time.
Upstream Speed = 2/1 = 2 km/hr.
Downstream Speed = 1KM/10Min = 1/(10/60)hr = 1/(1/6) Km/Hr = 6 Km/Hr.
Now, Speed in Still Water = 1/2 (a+b)
a = Upstream speed means the speed of the boat against the current of the stream.
b. = Downstream speed means boat speed along the stream
= 1/2(2+6) after simplifying and is 4 Km/hr.
Total time required to travel distance of 5km for a boat in stationary water will be?
Time = Distance / Speed ----> Formula.
= 5/4 -> 4 km/hr is the speed of the boat in stationary water & 5 Km be the distance.
= 1.25 hr => 1 hr 15 min.
25/100 *60 = 15 for a minute to hour conversation.
Upstream Speed = 2/1 = 2 km/hr.
Downstream Speed = 1KM/10Min = 1/(10/60)hr = 1/(1/6) Km/Hr = 6 Km/Hr.
Now, Speed in Still Water = 1/2 (a+b)
a = Upstream speed means the speed of the boat against the current of the stream.
b. = Downstream speed means boat speed along the stream
= 1/2(2+6) after simplifying and is 4 Km/hr.
Total time required to travel distance of 5km for a boat in stationary water will be?
Time = Distance / Speed ----> Formula.
= 5/4 -> 4 km/hr is the speed of the boat in stationary water & 5 Km be the distance.
= 1.25 hr => 1 hr 15 min.
25/100 *60 = 15 for a minute to hour conversation.
(1)
Manideep said:
7 years ago
Thank you @Sonia.
Sonia said:
8 years ago
1hr = 60mins.
So, 1/4 of 1 hr = 1/4*60= 15min.
So, 1/4 of 1 hr = 1/4*60= 15min.
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