Aptitude - Boats and Streams - Discussion

Discussion Forum : Boats and Streams - General Questions (Q.No. 11)
11.
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
40 minutes
1 hour
1 hr 15 min
1 hr 30 min
Answer: Option
Explanation:

Rate downstream = 1 x 60 km/hr = 6 km/hr.
10

Rate upstream = 2 km/hr.

Speed in still water = 1 (6 + 2) km/hr = 4 km/hr.
2

Required time = 5 hrs = 1 1 hrs = 1 hr 15 min.
4 4

Discussion:
27 comments Page 2 of 3.

Lohith said:   10 years ago
s = d/t;
u-v = 2/1;

u-v = 2.
u+v = 2/10/60.
u+v = 12.

u = 7.
v = 5.

Final value = 5/7 which is less than a hour.

Sravankumar said:   1 decade ago
We caluculate required time by using this formule

t=l/s.

Here t=5km/4hrs leads to (5/4)km per hour

Darth vadar said:   9 years ago
Divide 5 by 4 we get 0.25. So why the answer is 1 hr 15 min instead of 1 hr 25 min.

Kiran said:   8 years ago
The ans must be 1hr 25mins.
5/4=1.25.
How it can be 1hr 15mins?
(2)

Ibrana said:   6 years ago
Please discuss the proper way to find required time.

Kessy said:   5 years ago
Anyone, please explain this step 1/2 times (6 + 2).

Thomas said:   6 years ago
I also agree, The answer should be 1h and 25 mins.
(3)

Sonia said:   8 years ago
1hr = 60mins.

So, 1/4 of 1 hr = 1/4*60= 15min.

Hasi said:   3 months ago
I agree that the answer will be 1 hour 25 min.

Kas said:   1 decade ago
How to calculate the required time ?


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