Aptitude - Average - Discussion
Discussion Forum : Average - Data Sufficiency 1 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
1.
The average age of P, Q, R and S is 30 years. How old is R? | |
I. | The sum of ages of P and R is 60 years. |
II. | S is 10 years younger than R. |
Answer: Option
Explanation:
P + Q + R + S = (30 x 4) P + Q + R + S = 120 .... (i)
I. P + R = 60 .... (ii)
II. S = (R - 10) .... (iii)
From (i), (ii) and (iii), we cannot find R.
Correct answer is (D)
Discussion:
25 comments Page 3 of 3.
Pritymoy said:
1 decade ago
Sandeep is right.
Sonal and sandip are both fail to understand the assumptions.
Sonal and sandip are both fail to understand the assumptions.
Sandeep said:
1 decade ago
Option D is only correct answer not E @sandip and sonal tiwari u both have taken wrong step at assumption I p+r=60
Shyam said:
1 decade ago
How? I can't get.
Sandip said:
1 decade ago
p+q+r+s=30*4
p+q=60.....(1)
s=r-10......(2)
so,60+r+(r-10)=120
=>r=35....so,correct ans is (E)
p+q=60.....(1)
s=r-10......(2)
so,60+r+(r-10)=120
=>r=35....so,correct ans is (E)
Magesh said:
1 decade ago
Correct Ans is E as discussed above
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