Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 12)
12.
The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
47.55 kg
48 kg
48.55 kg
49.25 kg
Answer: Option
Explanation:
Required average
= 50.25 x 16 + 45.15 x 8
16 + 8
= 804 + 361.20
24
= 1165.20
24
= 48.55
Discussion:
31 comments Page 3 of 4.

Nitin said:   9 years ago
Can be simply done by allegation rule.

50.25 45.15
\ /
\ /
X
/ \
/ \
2 1

NOW, (X - 45.25)/(50.25 - X) = 2/1 i.e. x = 48.55.
(1)

Shelly said:   9 years ago
Guys the ratio is divided in 2:1. Now use allegation method.

Bala Mayak said:   8 years ago
Superb, nice explanation @Pavan.

Sunita said:   8 years ago
Let's take X=50.25 and Y=45.15.

It's given avg of 16 mem is 50.25 so X= 16*50.25 = 804 and in the same manner 8 member Y= 45.15*8 = 361.2.

The total members are 24 therefore;
AVERAGE = (804+361.2)/24 = 48.55.

Sirisha said:   7 years ago
Nice trick, Thanks @Pavan.

Siddhant said:   7 years ago
Sum a/16=50.35,
Sum b/8=45.15,
Sum a=50.35*16,
Sum a=804,
Sum b=45.15*8,
Sum b=361.2.
AVG=Suma+Sumb/16+8.
AVG=801+361.2/24,
AVG=48.55.
(1)

Vijay said:   7 years ago
Hi, I am not getting the answer. Can anyone explain me to get it?

Shubham j said:   7 years ago
16 boys having avg. wt. of : 50.25, i.e 50.25 * 16 = 804.
8 boys having avg. wt. of : 45.15 i.e 45.15 * 8 = 361.2.

804+361.2=1165.2.
1165.2/24 = 48.55 (24 is total boys).
(1)

Sree ranga said:   6 years ago
50.25 * 16 + 45.15 = x * 24,
804+361.2 = x * 24,
1165.2/24 = x,
X = 48.55.
(1)

Ishwar said:   5 years ago
The avg weight of 16 boys is 50.25, then the sum of wt of all 16 boys is 50.25 * 16 = 804.
The avg wt of remaining 8 boys is 45.15, then the sum of wt of all 8 boys is 45.15 * 8 = 361.2 .
Total boys in a class is 804+361.2 = 1165.2.
And the whole avg is 1165.2/(16+8) = 48.55.
(5)


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