Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 12)
12.
The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
Answer: Option
Explanation:
| Required average |
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| = 48.55 |
Discussion:
33 comments Page 1 of 4.
Ishwar said:
5 years ago
The avg weight of 16 boys is 50.25, then the sum of wt of all 16 boys is 50.25 * 16 = 804.
The avg wt of remaining 8 boys is 45.15, then the sum of wt of all 8 boys is 45.15 * 8 = 361.2 .
Total boys in a class is 804+361.2 = 1165.2.
And the whole avg is 1165.2/(16+8) = 48.55.
The avg wt of remaining 8 boys is 45.15, then the sum of wt of all 8 boys is 45.15 * 8 = 361.2 .
Total boys in a class is 804+361.2 = 1165.2.
And the whole avg is 1165.2/(16+8) = 48.55.
(7)
PavaN said:
1 decade ago
I you understand the concept then u can do like this also.. its easy too
16:8 = 2:1
then, (50.25x2 + 45.15x1) / (2+1) = 48.55
16:8 = 2:1
then, (50.25x2 + 45.15x1) / (2+1) = 48.55
(5)
Samreen hadimani said:
11 months ago
50.16 * 16 = 804.00.
45.15 * 8 = 361.20.
[804.00 + 361.20] = 1165.20 kg.
16 + 8 = 24 Total boy's.
= sum/total number,
= 1165.20/24,
= 48.55kg.
45.15 * 8 = 361.20.
[804.00 + 361.20] = 1165.20 kg.
16 + 8 = 24 Total boy's.
= sum/total number,
= 1165.20/24,
= 48.55kg.
(3)
Shubham j said:
7 years ago
16 boys having avg. wt. of : 50.25, i.e 50.25 * 16 = 804.
8 boys having avg. wt. of : 45.15 i.e 45.15 * 8 = 361.2.
804+361.2=1165.2.
1165.2/24 = 48.55 (24 is total boys).
8 boys having avg. wt. of : 45.15 i.e 45.15 * 8 = 361.2.
804+361.2=1165.2.
1165.2/24 = 48.55 (24 is total boys).
(2)
Siddhant said:
8 years ago
Sum a/16=50.35,
Sum b/8=45.15,
Sum a=50.35*16,
Sum a=804,
Sum b=45.15*8,
Sum b=361.2.
AVG=Suma+Sumb/16+8.
AVG=801+361.2/24,
AVG=48.55.
Sum b/8=45.15,
Sum a=50.35*16,
Sum a=804,
Sum b=45.15*8,
Sum b=361.2.
AVG=Suma+Sumb/16+8.
AVG=801+361.2/24,
AVG=48.55.
(1)
Avneet said:
9 years ago
16 Boys = 50.25 KG
8 Boys = 45.15 KG
Total boys and their weight is;
16B + 8B = (50.25 * 16) + (45.15 * 8).
24B = 1165.2.
B = 48.55.
8 Boys = 45.15 KG
Total boys and their weight is;
16B + 8B = (50.25 * 16) + (45.15 * 8).
24B = 1165.2.
B = 48.55.
(1)
Nitin said:
9 years ago
Can be simply done by allegation rule.
50.25 45.15
\ /
\ /
X
/ \
/ \
2 1
NOW, (X - 45.25)/(50.25 - X) = 2/1 i.e. x = 48.55.
50.25 45.15
\ /
\ /
X
/ \
/ \
2 1
NOW, (X - 45.25)/(50.25 - X) = 2/1 i.e. x = 48.55.
(1)
Shelly said:
9 years ago
Guys the ratio is divided in 2:1. Now use allegation method.
(1)
KIRAN KUMAR said:
10 years ago
This is a weighted average problem. In weighted average problem the value of the actual weights is not required. The ratio of the weights also will give you the same answer. Thus instead of 8 and 16 we can take the ratios of 8 and 16. i.e. 2 and 1 as our weights.
(1)
Bhawani said:
10 years ago
You can also solve in this type.
16 * 50.25 + 8 * 45.15 / 24.
8 (2 * 50.25 + 45.15) / 24.
145.75 / 3.
=> 48.55
16 * 50.25 + 8 * 45.15 / 24.
8 (2 * 50.25 + 45.15) / 24.
145.75 / 3.
=> 48.55
(1)
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