Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 12)
12.
The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
47.55 kg
48 kg
48.55 kg
49.25 kg
Answer: Option
Explanation:
Required average
= 50.25 x 16 + 45.15 x 8
16 + 8
= 804 + 361.20
24
= 1165.20
24
= 48.55
Discussion:
31 comments Page 2 of 4.

Prasad said:   10 years ago
Why can't we take both weights as individual weights?

i.e 50.25+45.15 = 95.40.

= 95.40/2 = 47.7 kg.

This process is wrong then say what is missing?

Samreen hadimani said:   5 months ago
50.16 * 16 = 804.00.
45.15 * 8 = 361.20.
[804.00 + 361.20] = 1165.20 kg.
16 + 8 = 24 Total boy's.
= sum/total number,
= 1165.20/24,
= 48.55kg.
(1)

Gokul Sreekumar said:   1 decade ago
A more simple way.

Instead of doing these complex multiplications you can simply take (50.25+50.25+45.15) /3 & you will get the answer.

Avneet said:   9 years ago
16 Boys = 50.25 KG
8 Boys = 45.15 KG

Total boys and their weight is;

16B + 8B = (50.25 * 16) + (45.15 * 8).
24B = 1165.2.
B = 48.55.
(1)

Siddhant said:   7 years ago
Sum a/16=50.35,
Sum b/8=45.15,
Sum a=50.35*16,
Sum a=804,
Sum b=45.15*8,
Sum b=361.2.
AVG=Suma+Sumb/16+8.
AVG=801+361.2/24,
AVG=48.55.
(1)

PavaN said:   1 decade ago
I you understand the concept then u can do like this also.. its easy too

16:8 = 2:1

then, (50.25x2 + 45.15x1) / (2+1) = 48.55
(4)

Madhavi said:   1 decade ago
@heema

It can also be solved sing the following formula:n1x1+n2x2/n1+n2....... n1=16,n2=8,x1=50.25 & x2=45.15

Bhawani said:   9 years ago
You can also solve in this type.

16 * 50.25 + 8 * 45.15 / 24.

8 (2 * 50.25 + 45.15) / 24.

145.75 / 3.

=> 48.55
(1)

Rajwinder singh said:   1 decade ago
Difference between 50.25 & 45.15 is 5.1.

16*5.1 = 81.6.
81.6/24 = 3.40.
45.15+3.40 = 48.55.
(1)

Priyanka said:   1 decade ago
How total boys 24 remaining 8 boys means? Boys inside 16 or separate 8 boys? Please explain.


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