### Discussion :: Average - General Questions (Q.No.14)

Muneer.S said: (Sep 21, 2012) | |

Total marks of first batch(55) is= 55*50=2750 Total marks of second batch (60)is= 60*55=3300 Total marks of third batch(45)= 45*60=2700 Total marks of second batch= 2750+3300+2700 = 8750 Total number of Students= 55+60+45 =160 Avg= 8750/160= 54.68 |

Madan said: (Jul 23, 2013) | |

Average of Batch A = 55+60+45 = 160. Average of Batch B = 50+55+60 = 165. Average marks of all the students is = 160+165/6. |

S.Balasubramaniam said: (Jan 3, 2014) | |

Average of batch A & B = 55*50+60*55+45*60/55+60+45. Total average number of batch = 8750/160. Total average = 54.68. |

Swordist said: (May 27, 2014) | |

Total marks of first batch(55) is = 55*50 = 2750. Total marks of second batch (60)is = 60*55 = 3300. Total marks of third batch(45) = 45*60 = 2700. Total marks of second batch = 2750+3300+2700 = 8750. Total number of Students = 55+60+45 = 160. Avg = 8750/160 = 54.6875 = 54.69. Answer: D. |

Vicky said: (Jun 17, 2016) | |

Thanks, @Balasubramaniam. |

Riyaz said: (Aug 15, 2016) | |

Thank you all who has given suggestions while solving the problems. |

Bhavik Oza said: (Nov 14, 2016) | |

Average marks are asked. So how can 160 come in the denominator? If you keep 160 then you will get average students as your answer. |

Sadhya said: (Aug 12, 2017) | |

I tell trick here given students 55 60 45 . avg marks 50 55 60. let assume average as 50. first 55 students. avg 50 given ok.but in case of next 60 members avg 55 given that means 60*5 = 300 extra .in case of remaining 45 students given 60 .that means 45*10 = 450 extra.totally 300 + 450 = 750 extra. 750 extra on 160 students so 750/160 = 4.68.finally 50 + 4.68 = 54.68 answer. |

Keshav Singh said: (Sep 14, 2017) | |

Thanks @S. Balasubramaniam. |

Swa said: (Mar 15, 2018) | |

Thank you @Sadhya. |

Pranay Rk said: (Jul 30, 2018) | |

It is clearly written 55, 60, 45 are total no of students. (i.e) 160 total student. Whereas average marks of the student are 50, 55, 60. |

Dr.R.Baskaran said: (Aug 3, 2018) | |

55: 60:45 = 11:12:9. Choose the origin (assumed average) as 55. The sum of the deviations = 11x(-5) + 9x5 = -10. Average = 55 - 10/(11 + 12 + 9) = 55 - 10/32. You have to subtract about 1/3 which is nearly 0.33. The answer is 54.68. |

Vijay Solanki said: (Aug 10, 2019) | |

Let, 1st batch = A , 2nd batch = B , 3rd batch = C, Now, A/55 = 50 => A= 2750 ( These are the Total marks of each batch of students ). B/60 = 55 => B= 3300 ( These are the Total marks of each batch of students ). C/45 = 60 => C= 2700 ( These are the Total marks of each batch of students ). From above total marks of all batches => A+B+C = 2750+3300+2700 =>8750. So, Total marks = 8750. Total number of students in all 3 batches => 55+60+45 =160. So, now we have to find average of all the students for that we will do, Total marks / Total number of students = 8750 / 160 => 54.68. Answer is option (B) = 54.68. |

Hari said: (Jan 13, 2020) | |

I am not understanding this, Anyone can explain it? |

Bosski said: (Jan 18, 2020) | |

Let assume average as 50. First 55 students. Here Avg 50 is given. But in case of next 60 members avg 55 given that means 60*5 = 300 extra. In case of remaining 45 students given 60.45*10 = 450 extra. And totally 300 + 450 = 750 extra. 750 extra on 160 students so 750/160 = 4.68. And 50 + 4.68 = 54.68 answer. |

Srid said: (Nov 15, 2020) | |

Let T be total marks if all pupil, N be no of students, A be the average mark. Case 1( when marks were entered correctly ie 63). T/N=A. Case 2(83) (T+20)/N=A+0.5. Subtract both equations. 20/N = 0.5. N= 40. |

Sourav said: (Jun 24, 2021) | |

Given students 55 60 45. average marks 50 55 60. You can take ratios of student in each batch. i.e. 11 :12 : 9 (55/5:60/5:45/5). Now solve; => 50x11+55x12+60x9 / (11+12+9), => 550+660+540/(32), => 1750/32, => 54.68. |

Seema said: (Sep 28, 2021) | |

Given; Student 55 60 45 Average marks 50 55 60 According to formula;- avg=sum/no Then; avg = sum of marks(165)/ no of student(3). Result comes 55. |

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