Aptitude - Average - Discussion

I suggest the answer may be 10.

Eg. If Avg of 20 numbers can be denoted as:

a + b + c + d + e + f + g + h + I + j + k + l + m + n + o + p + q + r + s + t.

Between j and k the zero will be present because we know that middle number will be the average.

So when zero is present after j so from k the number is greater than zero.

So the answer will be assumed as 10.

1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1-19.

0>1

Here 1 is 19
Negative number -19

SO answer is 19.

Why don't all you guys understand that, the question is being asked on the basis of "at the most". I too do agree that, there may be chances of more than one number of appropriate positive and negative number i.e. ten positive and ten negative, fifteen positive and five negative etc. But for at the most, the answer will be 19.

Because there will be the one negative number of all 19 positive number, so that the sum become zero. For the very beginning I also used to think like what you guys thinking now. Hope you will understand.

I think the solution is wrong as its just a assumption that out of 20 only one is 20. But it may also occurs that out of 20 10 may be positive and rest be negative.

Average of 20 numbers = (Sum of 20)/20.

Sum of 20 numbers = (20*21)/2.

So A/Q === (20*21)/(2*20) = 0.

=> 21/2 = 0.

=> 21 = 0.

Not possible :-).

@Hema.

Can you explain me your method once again?

@Sandeep.

They have asked "AT MOST how many numbers, may be greater than 0". At most, as in maximum how many numbers can be greater than 0.

What if there is 10 positive numbers and 10 negative numbers? Then the answer may be 10.

If -1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1+19 = 0.

Then 0/20 = 0.

Then positive number is only 1. Then answer is B.

Here in this question they asked about the almost that means max numbers of numbers those are greater than 0.

>>> So 19 is the answer because we are not considering the 0 because he asked >0.

>>> If he ask about min number of numbers we can say 1.

In this question how the sum of numbers can be greater than 0 and I did not understand the statement also explain please.