Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 4)
4.
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Answer: Option
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
Discussion:
135 comments Page 14 of 14.
Praveen said:
1 decade ago
@ hema ...
see here the sum is zero ...
sum of 20 numbers has to be 0
ex: 1+2+3+4+5+6...+20 = 0
let 1+2+3+4+5...19=a and the 20th number should be '-a' in order to get the sum as zero .
(a(1st 19numbers)-a(last 20th munber)=0 , hence a-a=0)
hence all 1st 19 numbers are positive means greater than zero and the last 20th is negative .
hence answer is 19 positive i.e greater than zero numbers.
see here the sum is zero ...
sum of 20 numbers has to be 0
ex: 1+2+3+4+5+6...+20 = 0
let 1+2+3+4+5...19=a and the 20th number should be '-a' in order to get the sum as zero .
(a(1st 19numbers)-a(last 20th munber)=0 , hence a-a=0)
hence all 1st 19 numbers are positive means greater than zero and the last 20th is negative .
hence answer is 19 positive i.e greater than zero numbers.
(2)
Raghav said:
1 decade ago
@ Jeeva.
In question it s asked numbers greater than 0, how negative nos be greater than 0. Negative no is less than 0.
In question it s asked numbers greater than 0, how negative nos be greater than 0. Negative no is less than 0.
Jeevanandham said:
1 decade ago
Please try this:
Sum of 10 +ve no's + 10 -ve no's = 0
So, sum is zero.
The answer may be 20.
Sum of 10 +ve no's + 10 -ve no's = 0
So, sum is zero.
The answer may be 20.
Harika said:
1 decade ago
Hi Hema,
Here average of 20 numbers= 0.
So we have avg = sum/20.
That implies sum = 0.
Now for the sum of 20 numbers to be equal to zero, there may be all 19 numbers of them >0 and only one number which is -ve of all the 19 numbers sum.
So the answer is 19.
Hope you understood now.
All the best.
Here average of 20 numbers= 0.
So we have avg = sum/20.
That implies sum = 0.
Now for the sum of 20 numbers to be equal to zero, there may be all 19 numbers of them >0 and only one number which is -ve of all the 19 numbers sum.
So the answer is 19.
Hope you understood now.
All the best.
(1)
Hema said:
1 decade ago
I don't unterstand this answer. Please any one explain.
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