Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
76 comments Page 7 of 8.
Saila said:
1 decade ago
@Puskar,
You may go through Diego's answer for better understanding.
You may go through Diego's answer for better understanding.
Puskar prasun said:
1 decade ago
Guys! it should be 2x^2 instead of simply x^2? don't you all agree?
Peter said:
1 decade ago
@Rkbm your answer best answer.
SHARDUL said:
1 decade ago
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291.
x2 - 100x + 291 = 0.
(x - 97)(x - 3) = 0.
x = 3.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291.
x2 - 100x + 291 = 0.
(x - 97)(x - 3) = 0.
x = 3.
Rupam said:
1 decade ago
There is no intercrossing left. When we considered 60x +40x, aren't we considering the intercrossing too? Otherwise the lengths couldn't have been 60 and 40.
Rajan said:
1 decade ago
The road is in the shape of plus mark.
So area of 1st road is 60x.
So area of 2nd road is 40x.
But in the middle the square has been calculated twice above. So subtract that area x^2.
So area of 1st road is 60x.
So area of 2nd road is 40x.
But in the middle the square has been calculated twice above. So subtract that area x^2.
Ashish Malviya said:
1 decade ago
Cosidering Road parallel to 60m side Area :- 60x.
Cosidering Road parallel to 40m side Area :- 40x.
Common area :- x*x.
Hence :- 291=60x+40x-x*x.
Cosidering Road parallel to 40m side Area :- 40x.
Common area :- x*x.
Hence :- 291=60x+40x-x*x.
MAHI said:
1 decade ago
40*3=120
60*3=180
TOTAL=300
LESS=291
BALANCE=9 SQCM
THAT IS 3*3
ANS=3.
60*3=180
TOTAL=300
LESS=291
BALANCE=9 SQCM
THAT IS 3*3
ANS=3.
ARAVIND said:
10 years ago
Great explanation @Ayoosh.
Imran Shaikh said:
1 decade ago
How is this calculated ?
x2 - 100x + 291 = 0 ----------> (x - 97)(x - 3) = 0
x2 - 100x + 291 = 0 ----------> (x - 97)(x - 3) = 0
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