Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 7 of 8.
Ashish Malviya said:
1 decade ago
Cosidering Road parallel to 60m side Area :- 60x.
Cosidering Road parallel to 40m side Area :- 40x.
Common area :- x*x.
Hence :- 291=60x+40x-x*x.
Cosidering Road parallel to 40m side Area :- 40x.
Common area :- x*x.
Hence :- 291=60x+40x-x*x.
Koushik said:
1 decade ago
Excellent Ayoosh. Thank you very much.
Rupam said:
1 decade ago
There is no intercrossing left. When we considered 60x +40x, aren't we considering the intercrossing too? Otherwise the lengths couldn't have been 60 and 40.
SHARDUL said:
1 decade ago
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291.
x2 - 100x + 291 = 0.
(x - 97)(x - 3) = 0.
x = 3.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291.
x2 - 100x + 291 = 0.
(x - 97)(x - 3) = 0.
x = 3.
Abhi said:
1 decade ago
Ayoosh explaination really helped me. Thanks Ayoosh :)
Peter said:
1 decade ago
@Rkbm your answer best answer.
Puskar prasun said:
1 decade ago
Guys! it should be 2x^2 instead of simply x^2? don't you all agree?
Saila said:
1 decade ago
@Puskar,
You may go through Diego's answer for better understanding.
You may go through Diego's answer for better understanding.
Ankit said:
1 decade ago
Thanks prajwal.
ARAVIND said:
10 years ago
Great explanation @Ayoosh.
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