Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
76 comments Page 6 of 8.
Aaru said:
1 decade ago
Ayoosh your explaination is nice. I understood well now,
Nayan said:
2 decades ago
Thnks nakul.
Nakul gowda said:
2 decades ago
60x + 40x includes the intersection part twice..so to include the intersection part only once, subtract area of intersection part once, ie, x^2....got it yet..
Sujay ramesh said:
2 decades ago
Thanks ayoosh. Your explanation is good :).
Jhola said:
2 decades ago
Very good ayoosh.
Naju said:
2 decades ago
Draw the figure you can c two cross road intersect, so we need to subtract it.
Tanya said:
2 decades ago
Its because the area of 2 roads has come out to be 291m2. Rest of the explaination has been given by prajwal.
Shreya said:
2 decades ago
My doubt is
60x+40x-x2=291?.
60x+40x-x2=291?.
Prajwal said:
2 decades ago
I got it. Its because. 60 and 40 get multiplies to width and. Since there are two cross roads. There will be a common space for two roads. (width of two cross roads is width^2).
Hashmuddin said:
1 decade ago
x2 -100x +291=0
x2 -97x -3x +291=0
x(x -97)-3(x-97)=0
(x-97)(x-3)=0
x2 -97x -3x +291=0
x(x -97)-3(x-97)=0
(x-97)(x-3)=0
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