Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
2.91 m
3 m
5.82 m
None of these
Answer: Option
Explanation:

Area of the park = (60 x 40) m2 = 2400 m2.

Area of the lawn = 2109 m2.

Area of the crossroads = (2400 - 2109) m2 = 291 m2.

Let the width of the road be x metres. Then,

60x + 40x - x2 = 291

x2 - 100x + 291 = 0

(x - 97)(x - 3) = 0

x = 3.

Video Explanation: https://youtu.be/R3CtrAKGxkc

Discussion:
75 comments Page 6 of 8.

Noble Phelix said:   9 years ago
Good job @Ayoosh.

GAYATRI said:   9 years ago
@All.

Please draw the picture first.

Two roads intersecting each other like " + " sign not like "x" sign. One road has an area of 60x other one has 40x. There is a common area of x^2.
(1)

Vijeta said:   8 years ago
Nice explanation. Thank you all.

VAN said:   8 years ago
So, x is squared because it is assumed that the two x's are of equal value?

Salman said:   8 years ago
Thanks to all for giving the explanation.

Tamil said:   8 years ago
Well said @Ayoosh.

Bhargavi said:   8 years ago
When two roads intersecting like a +.
So road 1 area is l*b =60*x rectangle road 2 area is l*b =40*x rectangle intersecting place is in a square shape so side =x.; the area is x^2.

In road 1 and road2 we are calculating intersecting point area two times so we have to Subtract that square shape intersecting point.
(3)

Bond said:   8 years ago
Thanks @Ayoosh.

Torikul said:   8 years ago
Thanks for your good explanation @Priyanka.

Smita said:   8 years ago
Thanks @Ayoosh.


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