Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 5 of 8.
ARAVIND said:
9 years ago
Great explanation @Ayoosh.
Arjun said:
9 years ago
(60x + 40x -x^2 this is the area of cross roads alone. 60 and 4O are lengths of cross roads and x is the breadth.
X^2 is subtracted because the meeting of crossroads, the calculated area overlaps. So - X^2.
X^2 is subtracted because the meeting of crossroads, the calculated area overlaps. So - X^2.
Imtiyaj said:
9 years ago
God job @Ayoosh.
Lalitha said:
9 years ago
Thank you @Ayoosh.
Lavanya said:
9 years ago
@Ayoosh,
60 and 40 are not the lengths of the roads. 60 is the length and 40 is the width. Still, have a confusion. Could anyone please explain it clearly?
60 and 40 are not the lengths of the roads. 60 is the length and 40 is the width. Still, have a confusion. Could anyone please explain it clearly?
Ammu said:
9 years ago
Thanks for the explanation.
Savita said:
9 years ago
Thanks @Priyanka for the answer.
T BALAJI said:
9 years ago
Thank you @Ayoosh.
Aayushi said:
9 years ago
Where is 291?
How to solve this?
How to solve this?
Pratiti Das said:
9 years ago
How come two concentric roads have 60x + 40x?
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