Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 12)
12.
The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
Answer: Option
Explanation:
Let original length = x and original breadth = y.
Original area = xy.
| New length = | x | . |
| 2 |
New breadth = 3y.
| New area = |  |
x | x 3y |  |
= | 3 | xy. |
| 2 | 2 |
 Increase % = |
|
1 | xy x | 1 | x 100 | % |
= 50%. |
| 2 | xy |
Discussion:
25 comments Page 3 of 3.
Sri said:
1 decade ago
Thanks kanmani for your good explanation.
Adilakshmi said:
1 decade ago
Please explain clearly what is the formula used.
Arun said:
1 decade ago
Hey sri wat kanmani told is right
see new area =3/2xy
orginal area=xy
so (3/2xy-xy)/xy=.50%(i.e)50%
see new area =3/2xy
orginal area=xy
so (3/2xy-xy)/xy=.50%(i.e)50%
Sri said:
1 decade ago
Please explain in detail.
Isn't it.
New area/original area = (3/2xy) /xy.
Isn't it.
New area/original area = (3/2xy) /xy.
Kanmani said:
1 decade ago
Increase% = (new area-original)/original.
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