Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 12)
12.
The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
25% increase
50% increase
50% decrease
75% decrease
Answer: Option
Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x .
2

New breadth = 3y.

New area = x x 3y = 3 xy.
2 2

Increase % = 1 xy x 1 x 100 % = 50%.
2 xy

Discussion:
25 comments Page 2 of 3.

Kavish said:   1 decade ago
@Abc.

The area is obviously increasing in this case :

Take for example as given in this question.

At normal condition. When, L = x and B = y dn the area = xy,

While as per the conditions in question, L = x/2 and B = 3y dn the area = 3/2 (xy).

Dat means the area increases by 3/2 times of original area.

Further as you can see, change in area or increment in area = 3/2 (xy) -xy = 0.5xy.

Increase in percent = 0.5xy/xy *100 = 50%.

That's it.

Himanshuvijayvargia said:   1 decade ago
x + y + x*y/100 = % increase or decrease in the area of an image when there is any increase or decrease in its sides.

Here x =(-50%); y = (200%).

-50 + 200 + (-50*200/100) = +50% answer.

Rajan Maheshwari said:   1 decade ago
Its very simple:

Consider length and breadth to be 100.

So area should be 100 X 100 = 10,000 sq unit.

But according to given condition if length is halved then it becomes 50 (100/2) and breadth is tripled it becomes 300(100X3) So new area is 50 x 300= 1500 sq unit.

It is greater than the area if length and breadth were not altered. Therefore increase is there,

Secondly change is area is:

{(15000-10000)/10000}x 100 = 50%.

Devender said:   1 decade ago
In the formula x+y+xy/100. Y value should be 300. How it is taken 200. I am not getting answer.

Medha said:   1 decade ago
If we take l = 10 nd b = 10.
Area = l*b = 100.

Now the new length l/2 = 5.
And new breadth 3b = 30.

New area = 5*30 = 150.
Old area was 100 nd new is 150 so it increases by 50 which is double(new-Old = 150-100 = 50 it is 50% with respect to 100).

Means increases 50%.

Engr. Md. Easir Arafat said:   1 decade ago
Say, length to be x and breadth to be y.

After modification: Length becomes x/2 and breadth becomes 3y.

Previous Area, A' = xy and the New Area, A = {3/2*(xy)}.

Difference in Area, A-A' = 3/2 = 1.5 hence 50% increase.
(1)

Naga said:   1 decade ago
Assume L = 100, B = 80, L*B = 8000, Given data half length so, -50 breadth-3s = 3*80 = 240.

50*240 = 12000, change percentage = 12000-8000/80 = 50.

Sanjoy Kanrar said:   1 decade ago
Let, length = 100 and breadth = 100.

New area:Previous area = {(100/2)*(100*3)}:{100*100}.

= 150:100.

So increase = 50%.
(2)

Aparna said:   1 decade ago
Please explain me how the last step came.
(1)

Ash said:   9 years ago
Why x + y + xy/100 not taken?


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