Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
8 |
Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
8 |
![]() |
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
8 | 8 |
5x + 24 = 40 - 5x
10x = 16
![]() |
8 | . |
5 |
So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
5 | 8 | 5 |
Discussion:
198 comments Page 9 of 20.
Vky said:
1 decade ago
Here x=8/5 is the amount in liters that has been added to make up 8 liters in total. This added quantity constitutes some part of the total volume. Right? So, this some part is stated as (x/8). Hope everyone's doubt on this has been cleared. => (8/ (5*8) ) =1/5.
1/5th is the part (not liters) from the total 8liters that has been added. Thank You.
1/5th is the part (not liters) from the total 8liters that has been added. Thank You.
Chinmayi said:
1 decade ago
Formula for this type of question:.
(1/2) (difference in parts/greater part).
(1/2) (difference in parts/greater part).
Ami said:
1 decade ago
Suppose initial quantity of mixture is 1 lit.
ratio water:syrup = 3:5,so syrup is 3/8
alligation method
3/8 1(pure water so taken as 1)
1/2
1/2 1/8
qt of mixture 1/2
-------------= ---
qt of water 1/8
1-x/x=4,so x=1/5 (x= quatity of water removed or qt. of syrup
withdraw)
ratio water:syrup = 3:5,so syrup is 3/8
alligation method
3/8 1(pure water so taken as 1)
1/2
1/2 1/8
qt of mixture 1/2
-------------= ---
qt of water 1/8
1-x/x=4,so x=1/5 (x= quatity of water removed or qt. of syrup
withdraw)
Susmitha said:
1 decade ago
Here given 8 parts of total, 3 parts water &5 parts syrup. Then we equal the both water & syrup ratio. Now we add the 1 part of syrup from 5 parts of syrup i.e;1/5 then it will become equal parts of water & syrup.
The answer is:1/5.
The answer is:1/5.
Kousik Maji said:
1 decade ago
Here total mixture is(3+5)=8.
Now syrup=5/8 and water=3/8.
If we take some mixture and added same amount of water then amount of syrup will be 1/2 and water 1/2.
Now the amount of syrup present in removed mixture is 5/8-1/2=1/8.
Now 5/8 syrup present in mixture 1.
1/8 ........................(8/5)X(1/8)=1/5.
Now syrup=5/8 and water=3/8.
If we take some mixture and added same amount of water then amount of syrup will be 1/2 and water 1/2.
Now the amount of syrup present in removed mixture is 5/8-1/2=1/8.
Now 5/8 syrup present in mixture 1.
1/8 ........................(8/5)X(1/8)=1/5.
N.anusha said:
1 decade ago
Thanks @Kousik Maji for your good solution but I am confused with bellow sentence please give clear cut info.
1/8 ........................(8/5)X(1/8)=1/5.
1/8 ........................(8/5)X(1/8)=1/5.
Mathkamsutra said:
1 decade ago
@Kiran how you got 60% and 40%
If I do - (3/8)*100 it gives 37.5%, How you got 60 and 40?
If I do - (3/8)*100 it gives 37.5%, How you got 60 and 40?
Guru said:
1 decade ago
I think the issue with some of the guys here is they find these mathematical theories hard to understand. Let me make it simpler for them.
They didn't give the volume of vessel in the question so never mind that. The vessel contains 8 parts of liquids (i.e. - 3 parts of water and 5 parts of syrup).
What they are asking is to make the mixture into half water and half syrup i.e. - 4 parts of water and 4 parts of syrup. To make it happen you need to take 1 part of syrup out of the vessel (which is 1/5th of the total syrup) and add 1 part of water instead and thus you get the answer 1/5!
They didn't give the volume of vessel in the question so never mind that. The vessel contains 8 parts of liquids (i.e. - 3 parts of water and 5 parts of syrup).
What they are asking is to make the mixture into half water and half syrup i.e. - 4 parts of water and 4 parts of syrup. To make it happen you need to take 1 part of syrup out of the vessel (which is 1/5th of the total syrup) and add 1 part of water instead and thus you get the answer 1/5!
Rahul Wiley said:
1 decade ago
Hey Keep it simple.
Fraction of syrup in final Mixture = (Fraction of syrup in initial mixture)*(1 - x/v).
Where,
x is the Quantity of mixture removed.
V is the volume of the Mixture.
Fraction of syrup in final Mixture = (Fraction of syrup in initial mixture)*(1 - x/v).
Where,
x is the Quantity of mixture removed.
V is the volume of the Mixture.
Rajesh said:
1 decade ago
Simple friends,
Here totally 8 parts (5 part syrup + 3 part water).
To make it equal (4 parts syrup + 4 part water).
So, we have to draw 1 part from syrup (i.e.,) 1/5.
Here totally 8 parts (5 part syrup + 3 part water).
To make it equal (4 parts syrup + 4 part water).
So, we have to draw 1 part from syrup (i.e.,) 1/5.
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