Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
| Quantity of water in new mixture = |  |
3 - | 3x | + x |  |
litres |
| 8 |
| Quantity of syrup in new mixture = | |
5 - | 5x | |
litres |
| 8 |
 |
|
3 - | 3x | + x | |
= | |
5 - | 5x | |
| 8 | 8 |
5x + 24 = 40 - 5x
10x = 16
| x = |
8 | . |
| 5 |
| So, part of the mixture replaced = | |
8 | x | 1 | |
= | 1 | . |
| 5 | 8 | 5 |
Discussion:
198 comments Page 6 of 20.
Anand Shaw said:
1 decade ago
Water in one mixture : 3/8.
Water in another mixture : 1.
Water in new mixture : 1/2.
According allegation formula:
Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.
So 1/5 parts of another mixture is mixed with one.
Another mixture is pure and is same as mixture replaced.
Water in another mixture : 1.
Water in new mixture : 1/2.
According allegation formula:
Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.
So 1/5 parts of another mixture is mixed with one.
Another mixture is pure and is same as mixture replaced.
Abhishek Kumar JhaJi said:
2 years ago
Let 100 ltr mixture.
So, 5/8x 100 = 62.5 ltr syrup.
3/8x100 = 37.5 ltr water.
We need to remove syrup and add that much quantity of water so make it 1:1,
62.5- x/37.5+x = 1/1,
62.5- x = 37.5 +x.
2x = 25.
x = 12.5 (need to remove from syrup and this quantity into water),
12.5/62.5(syrup) = 1/5.
So, 5/8x 100 = 62.5 ltr syrup.
3/8x100 = 37.5 ltr water.
We need to remove syrup and add that much quantity of water so make it 1:1,
62.5- x/37.5+x = 1/1,
62.5- x = 37.5 +x.
2x = 25.
x = 12.5 (need to remove from syrup and this quantity into water),
12.5/62.5(syrup) = 1/5.
(54)
Anil said:
9 years ago
Quantity of syrup is 5. Quantity of water is 3. You have to add and subtract 1 from water quant and syrup quant respectively. Keep that one in numerator and the amount of which has to be reduced (syrup 5) should come in the denominator. 1/5. I have tried with other problems also it worked.
Kamaksha Puri said:
4 years ago
Let 100 ltr mixture.
So 5/8x 100=62.5 ltr syrup.
3/8x100= 37.5 ltr water.
We need to remove syrup and add that much quantity of water so make it 1:1
62.5- x/37.5+x=1/1,
62.5- x =37.5 +x.
2x =25.
x = 12.5 (need to remove from syrup and this quantity into water),
12.5/62.5(syrup) = 1/5.
So 5/8x 100=62.5 ltr syrup.
3/8x100= 37.5 ltr water.
We need to remove syrup and add that much quantity of water so make it 1:1
62.5- x/37.5+x=1/1,
62.5- x =37.5 +x.
2x =25.
x = 12.5 (need to remove from syrup and this quantity into water),
12.5/62.5(syrup) = 1/5.
(23)
Victor said:
1 decade ago
Simple solution for this;
Given: Vessel contains...water -- 3 parts. Syrup -- 5 parts.
Required: Both should be half-- half
Sol: take one part of syrup and add it to water i.e then both will have 4 parts.
So divide syrup into 5 parts.then one part is 1/5, that is the solution.
Given: Vessel contains...water -- 3 parts. Syrup -- 5 parts.
Required: Both should be half-- half
Sol: take one part of syrup and add it to water i.e then both will have 4 parts.
So divide syrup into 5 parts.then one part is 1/5, that is the solution.
(3)
Manish said:
1 decade ago
Let there be 1kg of mixture with water concentration 3/8 i.e. 3/8 kg water present.
X kg mixture is removed so water removed = 3X/8.
Now X kg pure water is added.
In the required mixture water = 1/2 kg. So balancing over water.
3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.
X kg mixture is removed so water removed = 3X/8.
Now X kg pure water is added.
In the required mixture water = 1/2 kg. So balancing over water.
3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.
Mir said:
6 years ago
When a mixture is drawn, both syrup and water is drawn equally.
So, if 1 part from water and 1 part of syrup(total 2 parts) is drawn, the ratio of 3:5 becomes 2:4. When replaced wit 2 parts of water, gives the ratio 4:4 i..e 1:1.
Therefore mixture drawn is 2/8 or 1/4.
So, if 1 part from water and 1 part of syrup(total 2 parts) is drawn, the ratio of 3:5 becomes 2:4. When replaced wit 2 parts of water, gives the ratio 4:4 i..e 1:1.
Therefore mixture drawn is 2/8 or 1/4.
(1)
Kiran said:
2 decades ago
As there are 3 parts of water and 5 parts of syrup.
total upto 8 parts.In terms of percentage,syrup is 60% and water is 40%.So syrup content to be reduced to 10% and water content to be increased to 10%,total constitutes to 10%+10%=20%.
finally 20%=20/100=1/5
total upto 8 parts.In terms of percentage,syrup is 60% and water is 40%.So syrup content to be reduced to 10% and water content to be increased to 10%,total constitutes to 10%+10%=20%.
finally 20%=20/100=1/5
(1)
Suresh said:
7 years ago
It's simple, but we can't understand what's meaning of question so the meaning of the question is how syrup is removed in the mixture.
So they said half water +half syrup=8.
Then syrup remove is 5-4 =1.
Then in ratio 1/5 parts of syrup is removed that's it.
So they said half water +half syrup=8.
Then syrup remove is 5-4 =1.
Then in ratio 1/5 parts of syrup is removed that's it.
Vishesh said:
5 years ago
The ratio of syrup and water is 3:5 after replacing it will half-half(equal) -> 1:1
Because we are adding only water so the ratio of syrup will be same then ratio 1:1 become
5:5 means 2 ratio water is adding, total ratio is 5 + 5=10.
So 2/10=1/5
Because we are adding only water so the ratio of syrup will be same then ratio 1:1 become
5:5 means 2 ratio water is adding, total ratio is 5 + 5=10.
So 2/10=1/5
(2)
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