Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
8 |
Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
8 |
![]() |
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
8 | 8 |
5x + 24 = 40 - 5x
10x = 16
![]() |
8 | . |
5 |
So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
5 | 8 | 5 |
Discussion:
198 comments Page 20 of 20.
Mansi said:
6 years ago
Very helpful, thanks for helping @Surendrareddy.
Tanmay said:
6 years ago
Can anyone Explain the formula used in these question?
Tanzid said:
6 years ago
3:5 becomes 4:4, So change in syrup is (5-4) in 5 units so = 1/5.
Andy said:
5 years ago
The ratio of water/syrup is 3:5.
So, 3/8-3x/8+x = 5/8-5x/8
Solving X, we get 1/5.
So, 3/8-3x/8+x = 5/8-5x/8
Solving X, we get 1/5.
Shivangi said:
5 years ago
Final(syrup)=initial(syrup)*(1-(qt_replaced/total_mix).
X is a mixture replaced with water.
p is the total quantity of mixture.
4/8=5/8(1-x/p).
We need to find x/p which is 1/5 i.e answer.
X is a mixture replaced with water.
p is the total quantity of mixture.
4/8=5/8(1-x/p).
We need to find x/p which is 1/5 i.e answer.
Tejas said:
5 years ago
According to me, the solution is;
Water : syrup
30. :50
Total =80 then if x ltr mixture we tack out then the remaining ratio will be 1:1 .So
Take option 1/4 then try 1/4of 80 =20, or we can say 20/80*100= 25% of every (water and syrup).
But here we get vale in fraction, 25%of 30 = 7.5 ., 25%of 50= 12.5,
so this value.
30 - 7.5 =. 22.5
50 - 12.5 = 37.5 + 20 = 57.5.
This value not in ratio 1:1.
So, here ve take vale 1/5 or we can say 20 %of every part. 30*1/5=6
50 * 1/5 = 10.
Thus.
50 - 10 = 40.
30 + 10 = 40 this is in Ratio 1:1.
Water : syrup
30. :50
Total =80 then if x ltr mixture we tack out then the remaining ratio will be 1:1 .So
Take option 1/4 then try 1/4of 80 =20, or we can say 20/80*100= 25% of every (water and syrup).
But here we get vale in fraction, 25%of 30 = 7.5 ., 25%of 50= 12.5,
so this value.
30 - 7.5 =. 22.5
50 - 12.5 = 37.5 + 20 = 57.5.
This value not in ratio 1:1.
So, here ve take vale 1/5 or we can say 20 %of every part. 30*1/5=6
50 * 1/5 = 10.
Thus.
50 - 10 = 40.
30 + 10 = 40 this is in Ratio 1:1.
Gokul Ramakrishnan said:
4 years ago
Well said, nice answer. Thanks @Kiran.
Prakash said:
4 years ago
Well said, Thank you so much @Ameer.
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