Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
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3
1
4
1
5
1
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Answer: Option
Explanation:

Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water.

Quantity of water in new mixture = 3 - 3x + x litres
8

Quantity of syrup in new mixture = 5 - 5x litres
8

3 - 3x + x = 5 - 5x
8 8

5x + 24 = 40 - 5x

10x = 16

x = 8 .
5

So, part of the mixture replaced = 8 x 1 = 1 .
5 8 5

Discussion:
198 comments Page 13 of 20.

Prakash.m said:   1 decade ago
I don't understand none of the method above said. Can anyone tell mathematically?

Rakesh jha said:   1 decade ago
@Anand shaw.

Your method is good. But last passage after 4:1 can you elaborate more?

Anand Shaw said:   1 decade ago
Water in one mixture : 3/8.

Water in another mixture : 1.

Water in new mixture : 1/2.

According allegation formula:

Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.

So 1/5 parts of another mixture is mixed with one.

Another mixture is pure and is same as mixture replaced.

Sadik shaik said:   1 decade ago
To make equal parts, we just take 1 part from syrup and replace with water to get 4 parts of water and 4 parts of syrup.

So we are replacing 1 part of syrup of 5 parts with water, so the answer is 1/5.

Ankita said:   1 decade ago
How is the equation solved?

i.e. How do we get, 5x+24? Can anybody explain?

Aatish said:   1 decade ago
Concentration = a(1 - y/x)^n.

Remaining Syrup/Total volume = Concentration.

a = contamination of original solution, here in this case is 3:5 Viz 3/8.

Since water is 3 parts and syrup is 5 part that means the solution is contaminated with 37.5% in terms of syrup.

Now, Concentration = 1/2 (since, 50 % solution is desired).

Therefore, Using the above formula,

1/2 = 3/8(1 - y/x).

Here y = quantity of mixture drawn off.
x = initial volume.

We don't know either so leave it as it is. Solving we get,

Y/x = 1/4.

Now, Y:x::1:4.

Therefore, y = 1/1+4 = 1/5.

i.e 1 part of solution has been drawn off for per 5 part of the solution.

Ankita said:   1 decade ago
Can anybody gives the easiest way of solving it?

Amar said:   1 decade ago
Easy solution :

3 parts + 5 parts = 8 parts.

For equality (3+1) parts + (5-1) parts = 4 parts (equals).

Hence we need to reduce 1 part that will be from 5 parts.

Hence : 1 (part)/5(parts) is reduced.

Hope you understand.

Manish said:   1 decade ago
Let there be 1kg of mixture with water concentration 3/8 i.e. 3/8 kg water present.

X kg mixture is removed so water removed = 3X/8.

Now X kg pure water is added.

In the required mixture water = 1/2 kg. So balancing over water.

3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.

Minisha said:   1 decade ago
Can anyone solve this equation for me?

3-3x/8+x = 5-5x/8


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