Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
8 |
Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
8 |
![]() |
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
8 | 8 |
5x + 24 = 40 - 5x
10x = 16
![]() |
8 | . |
5 |
So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
5 | 8 | 5 |
Discussion:
199 comments Page 13 of 20.
Dinesh said:
1 decade ago
Before going to shortcuts I explain some known facts about this question.
1. Only water is added and no effect on syrup.
2. So think like how much water is added so that mixture is 1:1.
Lets start my shortcuts:
Water:Syrup 3:5.
After mixing water 1:1.
We know syrup has no loss and no gain so we first make part of syrup is 5. Hence we multiply by 5 in 1:1, we get 5:5.
Finally we see:
Before 3:5.
After 5:5.
Clearly we see that two part of water is added.
Hence amount of water added as new solution is gives answer.
2/10 = 1/5.
Trick is based on how much you think and how much you understand.
1. Only water is added and no effect on syrup.
2. So think like how much water is added so that mixture is 1:1.
Lets start my shortcuts:
Water:Syrup 3:5.
After mixing water 1:1.
We know syrup has no loss and no gain so we first make part of syrup is 5. Hence we multiply by 5 in 1:1, we get 5:5.
Finally we see:
Before 3:5.
After 5:5.
Clearly we see that two part of water is added.
Hence amount of water added as new solution is gives answer.
2/10 = 1/5.
Trick is based on how much you think and how much you understand.
Prakash.m said:
1 decade ago
I don't understand none of the method above said. Can anyone tell mathematically?
Rakesh jha said:
1 decade ago
@Anand shaw.
Your method is good. But last passage after 4:1 can you elaborate more?
Your method is good. But last passage after 4:1 can you elaborate more?
Anand Shaw said:
1 decade ago
Water in one mixture : 3/8.
Water in another mixture : 1.
Water in new mixture : 1/2.
According allegation formula:
Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.
So 1/5 parts of another mixture is mixed with one.
Another mixture is pure and is same as mixture replaced.
Water in another mixture : 1.
Water in new mixture : 1/2.
According allegation formula:
Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.
So 1/5 parts of another mixture is mixed with one.
Another mixture is pure and is same as mixture replaced.
Sadik shaik said:
1 decade ago
To make equal parts, we just take 1 part from syrup and replace with water to get 4 parts of water and 4 parts of syrup.
So we are replacing 1 part of syrup of 5 parts with water, so the answer is 1/5.
So we are replacing 1 part of syrup of 5 parts with water, so the answer is 1/5.
Ankita said:
1 decade ago
How is the equation solved?
i.e. How do we get, 5x+24? Can anybody explain?
i.e. How do we get, 5x+24? Can anybody explain?
Aatish said:
1 decade ago
Concentration = a(1 - y/x)^n.
Remaining Syrup/Total volume = Concentration.
a = contamination of original solution, here in this case is 3:5 Viz 3/8.
Since water is 3 parts and syrup is 5 part that means the solution is contaminated with 37.5% in terms of syrup.
Now, Concentration = 1/2 (since, 50 % solution is desired).
Therefore, Using the above formula,
1/2 = 3/8(1 - y/x).
Here y = quantity of mixture drawn off.
x = initial volume.
We don't know either so leave it as it is. Solving we get,
Y/x = 1/4.
Now, Y:x::1:4.
Therefore, y = 1/1+4 = 1/5.
i.e 1 part of solution has been drawn off for per 5 part of the solution.
Remaining Syrup/Total volume = Concentration.
a = contamination of original solution, here in this case is 3:5 Viz 3/8.
Since water is 3 parts and syrup is 5 part that means the solution is contaminated with 37.5% in terms of syrup.
Now, Concentration = 1/2 (since, 50 % solution is desired).
Therefore, Using the above formula,
1/2 = 3/8(1 - y/x).
Here y = quantity of mixture drawn off.
x = initial volume.
We don't know either so leave it as it is. Solving we get,
Y/x = 1/4.
Now, Y:x::1:4.
Therefore, y = 1/1+4 = 1/5.
i.e 1 part of solution has been drawn off for per 5 part of the solution.
Ankita said:
1 decade ago
Can anybody gives the easiest way of solving it?
Amar said:
1 decade ago
Easy solution :
3 parts + 5 parts = 8 parts.
For equality (3+1) parts + (5-1) parts = 4 parts (equals).
Hence we need to reduce 1 part that will be from 5 parts.
Hence : 1 (part)/5(parts) is reduced.
Hope you understand.
3 parts + 5 parts = 8 parts.
For equality (3+1) parts + (5-1) parts = 4 parts (equals).
Hence we need to reduce 1 part that will be from 5 parts.
Hence : 1 (part)/5(parts) is reduced.
Hope you understand.
Manish said:
1 decade ago
Let there be 1kg of mixture with water concentration 3/8 i.e. 3/8 kg water present.
X kg mixture is removed so water removed = 3X/8.
Now X kg pure water is added.
In the required mixture water = 1/2 kg. So balancing over water.
3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.
X kg mixture is removed so water removed = 3X/8.
Now X kg pure water is added.
In the required mixture water = 1/2 kg. So balancing over water.
3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.
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