Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
8 |
Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
8 |
![]() |
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
8 | 8 |
5x + 24 = 40 - 5x
10x = 16
![]() |
8 | . |
5 |
So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
5 | 8 | 5 |
Discussion:
198 comments Page 13 of 20.
Prakash.m said:
1 decade ago
I don't understand none of the method above said. Can anyone tell mathematically?
Rakesh jha said:
1 decade ago
@Anand shaw.
Your method is good. But last passage after 4:1 can you elaborate more?
Your method is good. But last passage after 4:1 can you elaborate more?
Anand Shaw said:
1 decade ago
Water in one mixture : 3/8.
Water in another mixture : 1.
Water in new mixture : 1/2.
According allegation formula:
Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.
So 1/5 parts of another mixture is mixed with one.
Another mixture is pure and is same as mixture replaced.
Water in another mixture : 1.
Water in new mixture : 1/2.
According allegation formula:
Ratio of quantity of two mixtures mixed : (3/8-1/2) : (1-1/2) = 4:1.
So 1/5 parts of another mixture is mixed with one.
Another mixture is pure and is same as mixture replaced.
Sadik shaik said:
1 decade ago
To make equal parts, we just take 1 part from syrup and replace with water to get 4 parts of water and 4 parts of syrup.
So we are replacing 1 part of syrup of 5 parts with water, so the answer is 1/5.
So we are replacing 1 part of syrup of 5 parts with water, so the answer is 1/5.
Ankita said:
1 decade ago
How is the equation solved?
i.e. How do we get, 5x+24? Can anybody explain?
i.e. How do we get, 5x+24? Can anybody explain?
Aatish said:
1 decade ago
Concentration = a(1 - y/x)^n.
Remaining Syrup/Total volume = Concentration.
a = contamination of original solution, here in this case is 3:5 Viz 3/8.
Since water is 3 parts and syrup is 5 part that means the solution is contaminated with 37.5% in terms of syrup.
Now, Concentration = 1/2 (since, 50 % solution is desired).
Therefore, Using the above formula,
1/2 = 3/8(1 - y/x).
Here y = quantity of mixture drawn off.
x = initial volume.
We don't know either so leave it as it is. Solving we get,
Y/x = 1/4.
Now, Y:x::1:4.
Therefore, y = 1/1+4 = 1/5.
i.e 1 part of solution has been drawn off for per 5 part of the solution.
Remaining Syrup/Total volume = Concentration.
a = contamination of original solution, here in this case is 3:5 Viz 3/8.
Since water is 3 parts and syrup is 5 part that means the solution is contaminated with 37.5% in terms of syrup.
Now, Concentration = 1/2 (since, 50 % solution is desired).
Therefore, Using the above formula,
1/2 = 3/8(1 - y/x).
Here y = quantity of mixture drawn off.
x = initial volume.
We don't know either so leave it as it is. Solving we get,
Y/x = 1/4.
Now, Y:x::1:4.
Therefore, y = 1/1+4 = 1/5.
i.e 1 part of solution has been drawn off for per 5 part of the solution.
Ankita said:
1 decade ago
Can anybody gives the easiest way of solving it?
Amar said:
1 decade ago
Easy solution :
3 parts + 5 parts = 8 parts.
For equality (3+1) parts + (5-1) parts = 4 parts (equals).
Hence we need to reduce 1 part that will be from 5 parts.
Hence : 1 (part)/5(parts) is reduced.
Hope you understand.
3 parts + 5 parts = 8 parts.
For equality (3+1) parts + (5-1) parts = 4 parts (equals).
Hence we need to reduce 1 part that will be from 5 parts.
Hence : 1 (part)/5(parts) is reduced.
Hope you understand.
Manish said:
1 decade ago
Let there be 1kg of mixture with water concentration 3/8 i.e. 3/8 kg water present.
X kg mixture is removed so water removed = 3X/8.
Now X kg pure water is added.
In the required mixture water = 1/2 kg. So balancing over water.
3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.
X kg mixture is removed so water removed = 3X/8.
Now X kg pure water is added.
In the required mixture water = 1/2 kg. So balancing over water.
3/8 " 3X/8 + X = 1/2 solving we get X = 1/5.
Minisha said:
1 decade ago
Can anyone solve this equation for me?
3-3x/8+x = 5-5x/8
3-3x/8+x = 5-5x/8
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