Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
| Quantity of water in new mixture = |  |
3 - | 3x | + x |  |
litres |
| 8 |
| Quantity of syrup in new mixture = | |
5 - | 5x | |
litres |
| 8 |
 |
|
3 - | 3x | + x | |
= | |
5 - | 5x | |
| 8 | 8 |
5x + 24 = 40 - 5x
10x = 16
| x = |
8 | . |
| 5 |
| So, part of the mixture replaced = | |
8 | x | 1 | |
= | 1 | . |
| 5 | 8 | 5 |
Discussion:
198 comments Page 10 of 20.
Ram said:
10 years ago
What if ratios are 2:1:2?
Vish said:
10 years ago
Quantity of syrup = x(1-y/x) raise to n, n = 2.
Here, 8(1-3/5) raise go 2.
= 4/5.
So quantity of water = 1-4/5 = 1/5.
Here, 8(1-3/5) raise go 2.
= 4/5.
So quantity of water = 1-4/5 = 1/5.
Vinod said:
10 years ago
Water : Syrup. 3:5.
Water = 3x.
Syrup = 5x.
Volume = 8x.
Why liters mixture withdrawn and replaced with water.
Applying the condition.
3x-3/8y+y = 5x-5/8y.
16x = 10y.
8x = 5y.
y = 8x/5.
y = Volume/5.
Water = 3x.
Syrup = 5x.
Volume = 8x.
Why liters mixture withdrawn and replaced with water.
Applying the condition.
3x-3/8y+y = 5x-5/8y.
16x = 10y.
8x = 5y.
y = 8x/5.
y = Volume/5.
Neeru said:
10 years ago
I think density of both ingredient is of some importance. That can be further related to concentration.
Jitendra said:
9 years ago
Let the volume of the mixture be 8 litres, in which 3 litre is water and 5 litres is syrup.
Now add 2 litre of water in the mixture, the volume becomes 10 litre and the ratio becomes 1:1.
Since the earlier mixture was 8 litre in volume.
Therefore we have to subtract 2 litres from the new mixture, so as it becomes 8 litres.
Now calculate how much part of the mixture was subtracted from the new mixture i.e. (2/10 or 1/5).
Now add 2 litre of water in the mixture, the volume becomes 10 litre and the ratio becomes 1:1.
Since the earlier mixture was 8 litre in volume.
Therefore we have to subtract 2 litres from the new mixture, so as it becomes 8 litres.
Now calculate how much part of the mixture was subtracted from the new mixture i.e. (2/10 or 1/5).
Raj said:
9 years ago
Actually the correct answer is 8/5.
Vishal said:
9 years ago
For 8 litre ---> full 1 part.
So, 8/5 litre --->?
So, 8/5 litre --->?
Bala said:
9 years ago
Hi, Can anyone clear my doubt?
How do they get this step?
Quantity of water in new mixture = 3 -((3x/8)+ x) litres.
How do they get this step?
Quantity of water in new mixture = 3 -((3x/8)+ x) litres.
Sandeep said:
9 years ago
Anyone, please clear my doubt.
How (3 - 3x / 8 + x) = 5x + 24?
How (3 - 3x / 8 + x) = 5x + 24?
Jomson joy said:
9 years ago
Thanks, vicllusion. It is the simple method.
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