Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: Option
Explanation:
Amount of milk left after 3 operations = | ![]() |
40 | ![]() |
1 - | 4 | ![]() |
3 | ![]() |
40 |
= | ![]() |
40 x | 9 | x | 9 | x | 9 | ![]() |
= 29.16 litres. |
10 | 10 | 10 |
Discussion:
67 comments Page 5 of 7.
N.M said:
3 years ago
I think we can understand this by the formula of successive discounts.
Am I right?
Am I right?
(7)
Puja said:
1 decade ago
It has given repeated twice, so three is taken as a power? Still not getting.
Sagar said:
9 years ago
Your logic is good Now, I can understand the solution. Thanks @Krishna.
Sahulions said:
1 decade ago
@Ramesh.
40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.
40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.
Shree said:
7 years ago
I get the solution with the help of given explanation, Thanks.
Vijay Karen said:
4 years ago
@Bhavna
17.7 is the answer for your question, Am I right?
17.7 is the answer for your question, Am I right?
(2)
Jon said:
1 decade ago
@Krisna
If in option there is 28.9 then what will you do?
If in option there is 28.9 then what will you do?
Shashank saraf said:
1 decade ago
Thanks dilip I understood the solution very well.
Nlff said:
1 decade ago
The description of the problem is ambiguous.
Ksanjeev said:
7 years ago
@Parvy Govil.
Very well explained. Thanks.
Very well explained. Thanks.
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