Aptitude - Alligation or Mixture - Discussion

How it is possible. Please explain.

I'm also confused.

The description of the problem is ambiguous.

Its a formula.

It's-

[a(1-x/a)n]

here a=initial quantity,
x=quantity taken out,
n=raised power of small bracket (no. of action
repeated)

Not getting the way its solved.

Could any body provide the procedure for solving it in another way rather than mugging up the formula.

Dont mind this is too long but i have a procedure to explain

Consider 3 times added water as 3 cases

case 1:after removal of milk and addition of water
water,milk are 4,36 lit ratio is 1:9

case2:when 4 lit are removed in that mix water,milk are (1/10)*4,(9/10)*4 of that mix
so presently water=4-2/5=18/5,milk=36-18/5=162/5
after addition of water,milk is same quantity but water=(18/5)+4
=38/4

case3:now ratio of water,milk=38:162=19:81
after removal of water,water,milk are (19/100)*4,(81/100)*4
so 19/25, 81/25
now milk=(162/5)-(81/25)=729/25=29.16 lit
antha length vodu anna dilogue gurthostundi kada so its simple to remember formula its better if we have only 1 or 2 cases

Given amount of milk = 40 lit.

Amount of milk taken out = 4 lit.

Remaining milk = 36 lit.

Given it is replaced with water and process repeated for twice.

Let us consider it is not replaced with water and process repeated for twice.

Then amount of milk = 36-4-4 = 28 lit.

Now logic:.

Now let us consider it is replaced with water and process repeated for twice.

Because of mixing water and taking 4 lit out from mixture, the amount of milk should be grater than 28 lit.

Only option (d) is greater than 28 lit.

Krishna your logic is good.