Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: Option
Explanation:
| Amount of milk left after 3 operations = |  |
40 |  |
1 - | 4 |  |
3 |  litres |
| 40 |
| = | |
40 x | 9 | x | 9 | x | 9 | |
= 29.16 litres. |
| 10 | 10 | 10 |
Discussion:
67 comments Page 5 of 7.
Jon said:
1 decade ago
@Krisna
If in option there is 28.9 then what will you do?
If in option there is 28.9 then what will you do?
Dinesh said:
1 decade ago
Krishna. Your idea is good.
SANTHOSH said:
1 decade ago
Krishna your logic is good.
Seema said:
1 decade ago
Only 2 times is given in the question. How can you say the action was repeated thrice and cube that.
Sravya said:
1 decade ago
Dont mind this is too long but i have a procedure to explain
Consider 3 times added water as 3 cases
case 1:after removal of milk and addition of water
water,milk are 4,36 lit ratio is 1:9
case2:when 4 lit are removed in that mix water,milk are (1/10)*4,(9/10)*4 of that mix
so presently water=4-2/5=18/5,milk=36-18/5=162/5
after addition of water,milk is same quantity but water=(18/5)+4
=38/4
case3:now ratio of water,milk=38:162=19:81
after removal of water,water,milk are (19/100)*4,(81/100)*4
so 19/25, 81/25
now milk=(162/5)-(81/25)=729/25=29.16 lit
antha length vodu anna dilogue gurthostundi kada so its simple to remember formula its better if we have only 1 or 2 cases
Consider 3 times added water as 3 cases
case 1:after removal of milk and addition of water
water,milk are 4,36 lit ratio is 1:9
case2:when 4 lit are removed in that mix water,milk are (1/10)*4,(9/10)*4 of that mix
so presently water=4-2/5=18/5,milk=36-18/5=162/5
after addition of water,milk is same quantity but water=(18/5)+4
=38/4
case3:now ratio of water,milk=38:162=19:81
after removal of water,water,milk are (19/100)*4,(81/100)*4
so 19/25, 81/25
now milk=(162/5)-(81/25)=729/25=29.16 lit
antha length vodu anna dilogue gurthostundi kada so its simple to remember formula its better if we have only 1 or 2 cases
Hary said:
1 decade ago
Could any body provide the procedure for solving it in another way rather than mugging up the formula.
Ram Prakash Keshri said:
1 decade ago
Not getting the way its solved.
Priya said:
1 decade ago
It's-
[a(1-x/a)n]
here a=initial quantity,
x=quantity taken out,
n=raised power of small bracket (no. of action
repeated)
[a(1-x/a)n]
here a=initial quantity,
x=quantity taken out,
n=raised power of small bracket (no. of action
repeated)
Nikki said:
1 decade ago
Its a formula.
Nlff said:
1 decade ago
The description of the problem is ambiguous.
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