Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
26.34 litres
27.36 litres
28 litres
29.16 litres
Answer: Option
Explanation:

Amount of milk left after 3 operations = 40 1 - 4 3  litres
40

   = 40 x 9 x 9 x 9 = 29.16 litres.
10 10 10

Discussion:
67 comments Page 7 of 7.

Sahulions said:   1 decade ago
@Ramesh.

40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.

Tanuz said:   10 years ago
If you are taking out 4 liters out of a 40 liter solution and replacing it with water, you are effectively replacing 1/10th of the solution with water.

=> Fraction of milk will become (9/10) of the original.

If the process is repeated 'n' times, fraction of milk will become (9/10)^n of the original.

We are given the process was done thrice.

Subhrangsu said:   10 years ago
Can it it solved by x and why quantity? like:

Currently, we have 36(M), 4(W). Now 4 litres is taken out.

So let milk remains: 36-x.

Water 4-(4-x).

Now add 4 litres water: so, milk = 36-x, water = [4-(4-x)]+4.

Again 4 litres taken out. Now suppose in that 4 lit why lit was milk. So milk remains: (36-x) -y and water = [[4-(4-x)]+4]-(4-y).

Now 4 lit water mixed so, milk = 36-x-y.

Water = [[4-(4-x)]+4]-(4-y)+4.

= [[4-4+x]+4]-4+y+4.

= [x+4+y].

But where is the problem in this approach? I just want to know that.

Pranav said:   10 years ago
Initial Status 1 => Milk = 40 {Volume = 40}.

Water = 0.

Iteration 1 => Milk = 40-4 = 36 {Volume = 40}.

Water = 4.

Fraction of water = 4/40 = 1/10.

Fraction of milk = 36/40 = 9/10.

Iteration 2 => Milk = 36-(9/10) 4 = 324/10 {Volume = 40}.

[Since 4 litres mixture has been removed].

Water = 4+(4-(1/10)4) = 76/10.

[Since 4 litres water has been added].

Fraction of water = (76/10)/40 = 76/400.

Fraction of milk = (324/10)/40 = 324/400.

Iteration 3 => Milk = 324/10-(324/400)4 = 729/25 = 29.16 {Vol = 40}.

[Since 4 litres mixture has been removed].

Water = 4+(76/10-(76/400) 4) = 271/25 = 10.84.

[Since 4 llitres water has been added].

Parvy Govil said:   10 years ago
First extract & refill. 36l milk, 4l water.

Milk in solution = 9/10; water = 1/10.

2nd extract: 4l taken out.

Milk = 9/10*4 = 3.6 water taken out = 0.4.

Milk remaining = 32.4, water remaining = 7.6.

Milk in solution = 32.4/40; water in solution = 7.6/40.

3rd extract: Milk extracted = 4*81/100.

Milk left will be 32.4-3.24 = 29.16.

Dean said:   10 years ago
It's just taking 10% away each time.

Munna said:   10 years ago
I don't understand why milk is getting reduced 10% each time while every time ratio of milk and water is getting changed.

Milk, water.

40, 0.

36, 4 10% of 40 is 4.

32.4, 7.6 10% of 36 is 3.6.

19.16 10% of 32.4 is 3.24.

Somebody please explain why percentage is constant?


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