Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: Option
Explanation:
Amount of milk left after 3 operations = | ![]() |
40 | ![]() |
1 - | 4 | ![]() |
3 | ![]() |
40 |
= | ![]() |
40 x | 9 | x | 9 | x | 9 | ![]() |
= 29.16 litres. |
10 | 10 | 10 |
Discussion:
67 comments Page 7 of 7.
Sahulions said:
1 decade ago
@Ramesh.
40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.
40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.
Tanuz said:
10 years ago
If you are taking out 4 liters out of a 40 liter solution and replacing it with water, you are effectively replacing 1/10th of the solution with water.
=> Fraction of milk will become (9/10) of the original.
If the process is repeated 'n' times, fraction of milk will become (9/10)^n of the original.
We are given the process was done thrice.
=> Fraction of milk will become (9/10) of the original.
If the process is repeated 'n' times, fraction of milk will become (9/10)^n of the original.
We are given the process was done thrice.
Subhrangsu said:
10 years ago
Can it it solved by x and why quantity? like:
Currently, we have 36(M), 4(W). Now 4 litres is taken out.
So let milk remains: 36-x.
Water 4-(4-x).
Now add 4 litres water: so, milk = 36-x, water = [4-(4-x)]+4.
Again 4 litres taken out. Now suppose in that 4 lit why lit was milk. So milk remains: (36-x) -y and water = [[4-(4-x)]+4]-(4-y).
Now 4 lit water mixed so, milk = 36-x-y.
Water = [[4-(4-x)]+4]-(4-y)+4.
= [[4-4+x]+4]-4+y+4.
= [x+4+y].
But where is the problem in this approach? I just want to know that.
Currently, we have 36(M), 4(W). Now 4 litres is taken out.
So let milk remains: 36-x.
Water 4-(4-x).
Now add 4 litres water: so, milk = 36-x, water = [4-(4-x)]+4.
Again 4 litres taken out. Now suppose in that 4 lit why lit was milk. So milk remains: (36-x) -y and water = [[4-(4-x)]+4]-(4-y).
Now 4 lit water mixed so, milk = 36-x-y.
Water = [[4-(4-x)]+4]-(4-y)+4.
= [[4-4+x]+4]-4+y+4.
= [x+4+y].
But where is the problem in this approach? I just want to know that.
Pranav said:
10 years ago
Initial Status 1 => Milk = 40 {Volume = 40}.
Water = 0.
Iteration 1 => Milk = 40-4 = 36 {Volume = 40}.
Water = 4.
Fraction of water = 4/40 = 1/10.
Fraction of milk = 36/40 = 9/10.
Iteration 2 => Milk = 36-(9/10) 4 = 324/10 {Volume = 40}.
[Since 4 litres mixture has been removed].
Water = 4+(4-(1/10)4) = 76/10.
[Since 4 litres water has been added].
Fraction of water = (76/10)/40 = 76/400.
Fraction of milk = (324/10)/40 = 324/400.
Iteration 3 => Milk = 324/10-(324/400)4 = 729/25 = 29.16 {Vol = 40}.
[Since 4 litres mixture has been removed].
Water = 4+(76/10-(76/400) 4) = 271/25 = 10.84.
[Since 4 llitres water has been added].
Water = 0.
Iteration 1 => Milk = 40-4 = 36 {Volume = 40}.
Water = 4.
Fraction of water = 4/40 = 1/10.
Fraction of milk = 36/40 = 9/10.
Iteration 2 => Milk = 36-(9/10) 4 = 324/10 {Volume = 40}.
[Since 4 litres mixture has been removed].
Water = 4+(4-(1/10)4) = 76/10.
[Since 4 litres water has been added].
Fraction of water = (76/10)/40 = 76/400.
Fraction of milk = (324/10)/40 = 324/400.
Iteration 3 => Milk = 324/10-(324/400)4 = 729/25 = 29.16 {Vol = 40}.
[Since 4 litres mixture has been removed].
Water = 4+(76/10-(76/400) 4) = 271/25 = 10.84.
[Since 4 llitres water has been added].
Parvy Govil said:
10 years ago
First extract & refill. 36l milk, 4l water.
Milk in solution = 9/10; water = 1/10.
2nd extract: 4l taken out.
Milk = 9/10*4 = 3.6 water taken out = 0.4.
Milk remaining = 32.4, water remaining = 7.6.
Milk in solution = 32.4/40; water in solution = 7.6/40.
3rd extract: Milk extracted = 4*81/100.
Milk left will be 32.4-3.24 = 29.16.
Milk in solution = 9/10; water = 1/10.
2nd extract: 4l taken out.
Milk = 9/10*4 = 3.6 water taken out = 0.4.
Milk remaining = 32.4, water remaining = 7.6.
Milk in solution = 32.4/40; water in solution = 7.6/40.
3rd extract: Milk extracted = 4*81/100.
Milk left will be 32.4-3.24 = 29.16.
Dean said:
10 years ago
It's just taking 10% away each time.
Munna said:
10 years ago
I don't understand why milk is getting reduced 10% each time while every time ratio of milk and water is getting changed.
Milk, water.
40, 0.
36, 4 10% of 40 is 4.
32.4, 7.6 10% of 36 is 3.6.
19.16 10% of 32.4 is 3.24.
Somebody please explain why percentage is constant?
Milk, water.
40, 0.
36, 4 10% of 40 is 4.
32.4, 7.6 10% of 36 is 3.6.
19.16 10% of 32.4 is 3.24.
Somebody please explain why percentage is constant?
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