Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: Option
Explanation:
| Amount of milk left after 3 operations = |  |
40 |  |
1 - | 4 |  |
3 |  litres |
| 40 |
| = | |
40 x | 9 | x | 9 | x | 9 | |
= 29.16 litres. |
| 10 | 10 | 10 |
Discussion:
67 comments Page 5 of 7.
Sahulions said:
1 decade ago
@Ramesh.
40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.
40(1-16/40)(1-10/40) = 18 litres milk and 22 litres of water.
Ramesh said:
1 decade ago
If the same amount of milk is drawn the formula is applicable but when different amounts of milk is drawn in different cases what have to do I have a problem here please solve this and explain.
There was 40 litres of pure milk in a vessel 16 litres of pure milk was taken out and replaced with equal amount of water again 10 litres of mixture was taken out and replaced with equal amount of water, what is the amount of water in the vessel now? (in litres).
There was 40 litres of pure milk in a vessel 16 litres of pure milk was taken out and replaced with equal amount of water again 10 litres of mixture was taken out and replaced with equal amount of water, what is the amount of water in the vessel now? (in litres).
Anvesh said:
1 decade ago
For this type of questions the formula is a(1-b/a) whole power n.
a = Initial quantity.
b = Taken out quantity.
n = Nor of times.
a = Initial quantity.
b = Taken out quantity.
n = Nor of times.
Puja said:
1 decade ago
It has given repeated twice, so three is taken as a power? Still not getting.
Sowmya said:
1 decade ago
First the milk had removed and replace by water it is 1 time later it had repeated for 2 times.
So total 1+2 = 3 times.
So the value of n is taken as 3.
So total 1+2 = 3 times.
So the value of n is taken as 3.
Ajay said:
1 decade ago
40 lit milk.
4 lit taken out.
36 lit milk and 4 lit water.
Again 4 lit mixture remove from total mixture.
4/ (total mixture = 40) --- 1 eqn.
36*4/40 = 3.6 milk and 4*4/40 = 0.4 water are remove.
Remaining milk = 32.4 (36-3.6) and water = 7.6 (8-0.4) lit.
Again same process as equation (1).
32.40-3.24 = 29.16 lit milk remains in mixture.
Simplest approach. !
4 lit taken out.
36 lit milk and 4 lit water.
Again 4 lit mixture remove from total mixture.
4/ (total mixture = 40) --- 1 eqn.
36*4/40 = 3.6 milk and 4*4/40 = 0.4 water are remove.
Remaining milk = 32.4 (36-3.6) and water = 7.6 (8-0.4) lit.
Again same process as equation (1).
32.40-3.24 = 29.16 lit milk remains in mixture.
Simplest approach. !
Sam said:
1 decade ago
40-4 == 36.
Now mixture contain 36 part milk and 4 part water.
36-4 = 32.
But all 4 part is not milk, it is mixture of water and milk.
In 4 part amount of water was=4*4/40=1*4/10=0.4.
So now milk = 32+0.4 = 32.4.
Process repeats one more time as follows:
Milk = 32.4-4 = 28.4.
This 4 is mixture of water and milk.
Water in this 4 lit is = 7.6*4/40 = 0.76.
So finally milk = 28.4+0.76 = 29.16.
Now mixture contain 36 part milk and 4 part water.
36-4 = 32.
But all 4 part is not milk, it is mixture of water and milk.
In 4 part amount of water was=4*4/40=1*4/10=0.4.
So now milk = 32+0.4 = 32.4.
Process repeats one more time as follows:
Milk = 32.4-4 = 28.4.
This 4 is mixture of water and milk.
Water in this 4 lit is = 7.6*4/40 = 0.76.
So finally milk = 28.4+0.76 = 29.16.
Nikita said:
1 decade ago
Why is 3 taken as the power whereas it should be 2 as its repeated two times. Someone please explain?
Manoj Kumar said:
1 decade ago
Hope guys. This will help you.
40-4 == taken out 10% milk == 36.
36-4 == taken out 10% milk == 32.40.
32.40 == taken out 10% milk == 29.16.
40-4 == taken out 10% milk == 36.
36-4 == taken out 10% milk == 32.40.
32.40 == taken out 10% milk == 29.16.
Seema said:
1 decade ago
Only 2 times is given in the question. How can you say the action was repeated thrice and cube that.
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