Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: Option
Explanation:
| Amount of milk left after 3 operations = |  |
40 |  |
1 - | 4 |  |
3 |  litres |
| 40 |
| = | |
40 x | 9 | x | 9 | x | 9 | |
= 29.16 litres. |
| 10 | 10 | 10 |
Discussion:
67 comments Page 7 of 7.
Hary said:
2 decades ago
Could any body provide the procedure for solving it in another way rather than mugging up the formula.
Ram Prakash Keshri said:
2 decades ago
Not getting the way its solved.
Priya said:
2 decades ago
It's-
[a(1-x/a)n]
here a=initial quantity,
x=quantity taken out,
n=raised power of small bracket (no. of action
repeated)
[a(1-x/a)n]
here a=initial quantity,
x=quantity taken out,
n=raised power of small bracket (no. of action
repeated)
Nikki said:
2 decades ago
Its a formula.
Nlff said:
2 decades ago
The description of the problem is ambiguous.
Umesh said:
2 decades ago
I'm also confused.
Anil said:
2 decades ago
How it is possible. Please explain.
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