Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 8)
8.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: Option
Explanation:
| Amount of milk left after 3 operations = |  |
40 |  |
1 - | 4 |  |
3 |  litres |
| 40 |
| = | |
40 x | 9 | x | 9 | x | 9 | |
= 29.16 litres. |
| 10 | 10 | 10 |
Discussion:
67 comments Page 3 of 7.
Manoj said:
9 years ago
Must follow this to all this type of questions.
4 lit drawn then ratio: 4/40 => 1/10.
Rest liquid: 9/10.
Total : Rest
(10) power 3 : 9 power is 3
Ratio becomes 1000 : 729.
Now according to question 1000 : 40,
then,
1 : 0.04
Rest liquid 729=> 729 * 0.04=> 29.16.
4 lit drawn then ratio: 4/40 => 1/10.
Rest liquid: 9/10.
Total : Rest
(10) power 3 : 9 power is 3
Ratio becomes 1000 : 729.
Now according to question 1000 : 40,
then,
1 : 0.04
Rest liquid 729=> 729 * 0.04=> 29.16.
Munna said:
10 years ago
I don't understand why milk is getting reduced 10% each time while every time ratio of milk and water is getting changed.
Milk, water.
40, 0.
36, 4 10% of 40 is 4.
32.4, 7.6 10% of 36 is 3.6.
19.16 10% of 32.4 is 3.24.
Somebody please explain why percentage is constant?
Milk, water.
40, 0.
36, 4 10% of 40 is 4.
32.4, 7.6 10% of 36 is 3.6.
19.16 10% of 32.4 is 3.24.
Somebody please explain why percentage is constant?
R.Saravanan said:
9 years ago
A venal contains a mixture of milk and water. Milk being 49% of the solution. Two times the mixture is taken out and replaced by water. Now the mixture contains only 9%of milk. How many litres of mixture is taken out?
Find the solution of the problem.
Find the solution of the problem.
Bhavna said:
6 years ago
A container has 60 litre of milk 20 litres are drawn out of the container every day and replaced by 20 litre of water what will be the quantity of milk left in the container at the end of the third day? Someone solve this question, please.
(3)
Bhargava Reddy said:
9 years ago
@Shobana.
Step1: 40-(10% of 40) = 36.
Step2: 36-(10% of 36) = 32.4.
Step3: 32.4-(10% of 32.4) = 29.16.
This is the simplest method. But if you want to understand the method clearly, go through my first comment.
Step1: 40-(10% of 40) = 36.
Step2: 36-(10% of 36) = 32.4.
Step3: 32.4-(10% of 32.4) = 29.16.
This is the simplest method. But if you want to understand the method clearly, go through my first comment.
(1)
Bir bahadur singh said:
8 years ago
Suppose a container contains x of liquid from which y units are taken out and replaced by water.
After n operations, the quantity of pure liquid =x(1 -(y-x )power n)) units.
After n operations, the quantity of pure liquid =x(1 -(y-x )power n)) units.
Bhargava reddy said:
9 years ago
@Munna: Here the key is every time we are removing same 4 L from the 40 L of mixture which constitutes to 10% of entire solution.
Hence the percentage remains constant.
Hence the percentage remains constant.
A9jo said:
1 decade ago
Suppose a container contains x of liquid from which y units are taken out and replaced by water.
After n operations, the quantity of pure liquid = x 1 - y n units.
After n operations, the quantity of pure liquid = x 1 - y n units.
Nandkishore said:
7 years ago
It's simple.
First, you take out 4ltr out of 40 ltr milk then mix 4ltr replace with water again you do further 2time means 4/40=36/40= (9/10) 3*40=29.16milk.
First, you take out 4ltr out of 40 ltr milk then mix 4ltr replace with water again you do further 2time means 4/40=36/40= (9/10) 3*40=29.16milk.
(1)
Nitin gusain said:
1 decade ago
@ Krishna.
Your logic is correct but if its options are changed logically then your logic gets fail.
Please give a more suitable and simple explanation.
Your logic is correct but if its options are changed logically then your logic gets fail.
Please give a more suitable and simple explanation.
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