Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 6 of 7.
Saidul said:
7 years ago
X:Y:Z=1:1:2 (total=4).
153tk/kg (total amount=153*4=612tk),
1st two(135+126=261tk),
3rd=612-261=351tk,
As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.)
153tk/kg (total amount=153*4=612tk),
1st two(135+126=261tk),
3rd=612-261=351tk,
As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.)
(2)
Naveen Gaddam said:
7 years ago
Give the ratio of three type of sugars are in =1:1:2.
1/4 kgs of the first two types and 2/4 kgs of third type sugar.
assume third type sugar price=x per kg.
(1/4)*126+(1/4)*135+ (2/4)*x=153.
(126+135+2x)/4 = 153.
261+2x=612..
2x=351.
x=175.50.
1/4 kgs of the first two types and 2/4 kgs of third type sugar.
assume third type sugar price=x per kg.
(1/4)*126+(1/4)*135+ (2/4)*x=153.
(126+135+2x)/4 = 153.
261+2x=612..
2x=351.
x=175.50.
(3)
Sathish said:
7 years ago
1 : 1 : 2.
So 126+135/2=130.5 third varity.
(1*126)+(1*126)+(2*130.5) = 612 total price.
612 - 126 - 135 = 351 third varity price.
351/2 = 175.5.
So 126+135/2=130.5 third varity.
(1*126)+(1*126)+(2*130.5) = 612 total price.
612 - 126 - 135 = 351 third varity price.
351/2 = 175.5.
(4)
Naveen said:
7 years ago
Simple formule:
(1:1:2)/4=153
(126+135+2X)/4 = 153,
261+2X = 4 * 153
261+2X = 612,
2X = 612-261,
2X = 351,
x = 175.5.
(1:1:2)/4=153
(126+135+2X)/4 = 153,
261+2X = 4 * 153
261+2X = 612,
2X = 612-261,
2X = 351,
x = 175.5.
(42)
Gopeswar said:
7 years ago
The basic mixture and alligation formulae say:
Average =(N1A1+N2A2+....+NnAn)/(N1+N2+.....Nn)
Therefore: 153=(126*1+135*1+2*x)/(1+1+2).
solve and find x, here x is the price of the third variety of price.
Average =(N1A1+N2A2+....+NnAn)/(N1+N2+.....Nn)
Therefore: 153=(126*1+135*1+2*x)/(1+1+2).
solve and find x, here x is the price of the third variety of price.
(5)
Boopathy said:
6 years ago
I am not understanding. Please explain to me.
(7)
Rachana said:
6 years ago
@Boopathy.
As the ratio given is 1:1:2.
So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule.
As the ratio given is 1:1:2.
So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule.
(2)
Rashmitha said:
6 years ago
Have anyone got 164.25 as answer.
(11)
Rakesh said:
5 years ago
Total units(1:1:2)= 1+1+2=4 (4kgs).
Total sum =avg * no. of units =153 * 4 = 612.
Remove first two =612-126-135 = 351.
Hence as the third variety holds 2 units (i.e. 2kgs).
1kg price = 351/2 =175.5.
In short:
Price of third variety = (153* 4 - 126 - 135)/2 =175.5.
Total sum =avg * no. of units =153 * 4 = 612.
Remove first two =612-126-135 = 351.
Hence as the third variety holds 2 units (i.e. 2kgs).
1kg price = 351/2 =175.5.
In short:
Price of third variety = (153* 4 - 126 - 135)/2 =175.5.
(180)
Niharika said:
5 years ago
Third Verity = x
126 * 1 + 135 * 1 + X * 2/1 + 1 + 2 = 153.
X = 175.50.
126 * 1 + 135 * 1 + X * 2/1 + 1 + 2 = 153.
X = 175.50.
(73)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers