Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 10)
10.
In what ratio must water be mixed with milk to gain 16
% on selling the mixture at cost price?
% on selling the mixture at cost price?
Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1.
| S.P. of 1 litre of mixture = Re.1, Gain = | 50 | %. |
| 3 |
 C.P. of 1 litre of mixture = |
 |
100 x | 3 | x 1 |  |
= | 6 |
| 350 | 7 |
By the rule of alligation, we have:
| C.P. of 1 litre of water C.P. of 1 litre of milk | |||||
| 0 | Mean Price
| Re. 1 | |||
|
|
||||
| Ratio of water and milk = |
1 | : | 6 | = 1 : 6. |
| 7 | 7 |
Discussion:
51 comments Page 2 of 6.
Maggi15 said:
1 decade ago
Agree with Dilip. The new ratio of 2 elements will be same as the profit/100. Say profit is 25% then the ratio will be 25/100 = 1/4. Hence, in 1000 litres of mixture, 200 litres of water + 800 litres of milk.
Supritha K.S. said:
1 decade ago
Why is C.P. of 1 liter of milk taken on the left hand side as per the rule of alligation in this problem. Unlike C.P. of 1 liter of milk which is taken on the right hand side in 6th sum and other sums?
Pari said:
7 years ago
CP+Profit=SP.
Profit gave =1/6.
SP of 1-litre mixture assumed to be Re1 and CP of 1-litre milk assumed to be Re1
CP+1/6 of CP = SP(which is assumed as 1).
So, CP comes out as 6/7.
Profit gave =1/6.
SP of 1-litre mixture assumed to be Re1 and CP of 1-litre milk assumed to be Re1
CP+1/6 of CP = SP(which is assumed as 1).
So, CP comes out as 6/7.
(1)
RIni said:
7 years ago
The amount of water =x litre.
Amount of milk= 100-x litre.
Profit= (x/(100-x))*100=50/3.
x=100/7=amount of water.
Amount of milk= 100-100/7=600/7.
The ratio of the amount of water to milk=1:6.
Amount of milk= 100-x litre.
Profit= (x/(100-x))*100=50/3.
x=100/7=amount of water.
Amount of milk= 100-100/7=600/7.
The ratio of the amount of water to milk=1:6.
(1)
Rohit Chaudhary said:
8 years ago
In what proportion must water be mixed with spirit to gain 9.09% by selling it at cost price. The quantity of water in the mixture of 1 litter is?
Can anyone help me to solve this question?
Can anyone help me to solve this question?
Paras said:
8 years ago
I too agree that it should be 5/6 instead of 6/7.
Same thing was done in 6th question where same logic was applied.
It gives ratio 1:5.
Please, anyone explain.
Same thing was done in 6th question where same logic was applied.
It gives ratio 1:5.
Please, anyone explain.
SUMIT VERMA said:
9 years ago
Let the cost price be Rs.100.
Since gain is Rs. 50/3.
So S.P is 100 + 50/3 = Rs.350/3.
Hence, Ratio = S.P - C.P/C.P, (350/3 - 100)/100 = 1/6.
Since gain is Rs. 50/3.
So S.P is 100 + 50/3 = Rs.350/3.
Hence, Ratio = S.P - C.P/C.P, (350/3 - 100)/100 = 1/6.
P K said:
5 years ago
Water always be the same amount, i.e, 100.
So the extra gain= mixed water, i.e, 50/3%.
water : milk = 50/3 : 100 = 50 : 300 = 1 : 6.
So the extra gain= mixed water, i.e, 50/3%.
water : milk = 50/3 : 100 = 50 : 300 = 1 : 6.
(29)
Moncy said:
1 decade ago
Can anyone please explain me how they took gain=50/3 as 350/3 while computing c.p of 1lt mixture..Please explain it for me...
Dilip said:
1 decade ago
Here the gain% is 16.66
i.e in 100 lit milk, 16.66 lit water is required to be added.
Hence ratio becomes, 16.66/100 = 1/6.
i.e in 100 lit milk, 16.66 lit water is required to be added.
Hence ratio becomes, 16.66/100 = 1/6.
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