Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 7)
7.
How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
Answer: Option
Explanation:
S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.
C.P. of 1 kg of mixture = Rs. |
![]() |
100 | x 9.24 | ![]() |
= Rs. 8.40 |
| 110 |
By the rule of allilation, we have:
| C.P. of 1 kg sugar of 1st kind Cost of 1 kg sugar of 2nd kind | ||
| Rs. 9 | Mean Price Rs. 8.40 | Rs. 7 |
| 1.40 | 0.60 | |
Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27
x = |
![]() |
7 x 27 | ![]() |
= 63 kg. |
| 3 |
Discussion:
42 comments Page 2 of 5.
Rangpur Road said:
7 years ago
(9x+27*7) =9.24(x+27)10/11.
By calculation x = 63.
By calculation x = 63.
(1)
Vikatakavee said:
1 decade ago
Unit C.P : Qty : Total Amount
Item 1. : 9 : x : 9x
Item 2. : 7 : 27 : 189
Mixture : 8.4 : x+27 : 8.4(x+27)
---> 9x+189 = 8.4x + 226.8.
---> 0.6 x = 37.8.
---> x = 63.
Item 1. : 9 : x : 9x
Item 2. : 7 : 27 : 189
Mixture : 8.4 : x+27 : 8.4(x+27)
---> 9x+189 = 8.4x + 226.8.
---> 0.6 x = 37.8.
---> x = 63.
(1)
MAZHAURL said:
1 decade ago
Since, at the profit of 10%,
Selling price tk 110 than cost price tk 100.
Selling price tk 1 than cost price tk 100/110.
Selling price tk 9. 24 than cost price tk 100*9.24/110 = 8.40.
Let, sugar will be mixed x kg.
X kg sugar at tk 9 than cost price will be tk 9x.
27 kg sugar at tk 7 than cost price will be tk 27*7 = 189.
Total cost price = (9x+189).
According to the question,
(9x + 189)/(x+27) = 8.40.
=> 9x + 189 = 8.40x+ 226.8.
=>. 60x = 37.80.
=> x = 63 kg.
Selling price tk 110 than cost price tk 100.
Selling price tk 1 than cost price tk 100/110.
Selling price tk 9. 24 than cost price tk 100*9.24/110 = 8.40.
Let, sugar will be mixed x kg.
X kg sugar at tk 9 than cost price will be tk 9x.
27 kg sugar at tk 7 than cost price will be tk 27*7 = 189.
Total cost price = (9x+189).
According to the question,
(9x + 189)/(x+27) = 8.40.
=> 9x + 189 = 8.40x+ 226.8.
=>. 60x = 37.80.
=> x = 63 kg.
(1)
Simran Mehta said:
6 years ago
@Jeyari.
By reducing it.
14:6- dividing both by 2 which gives 7:3.
By reducing it.
14:6- dividing both by 2 which gives 7:3.
(1)
Sushant said:
3 years ago
9.24 is sp with 10% profit.
Calculate cp with profit per cent formula;
Then, we get 8.4 cp.
Calculate cp with profit per cent formula;
Then, we get 8.4 cp.
(1)
Thakursaab said:
9 years ago
Let x kg of sugar is mixed with 27kg of sugar.
CP of mixture = x * 9 + 27 * 7,
SP of mixture = (x+27) * 9.24,
Now gain pecentage = ((sp-cp)/cp) * 100,
Put the values ,you will get the answer.
CP of mixture = x * 9 + 27 * 7,
SP of mixture = (x+27) * 9.24,
Now gain pecentage = ((sp-cp)/cp) * 100,
Put the values ,you will get the answer.
(1)
Andy said:
6 years ago
First get the mean or the cost price 9.24*110/110 = 8.4.
Then (27*7)+(9*x)/27+x = 8.4(average formula).
Solving x we get 63.
Then (27*7)+(9*x)/27+x = 8.4(average formula).
Solving x we get 63.
Shona said:
9 years ago
How 1st kind of sugar is taken as cheaper i.e. Rs. 9 and 2nd kind of sugar is taken dearer which is just of Rs. 7?
I could not understand how you are initiating the allegation formula.
Please help!
I could not understand how you are initiating the allegation formula.
Please help!
Naimul Samad said:
1 decade ago
(x * 9 + 27 * 7) * 110/100 = (x + 27) 9.24.
So, x = 63.
So, x = 63.
Jeyari said:
6 years ago
Could you please explain how ratio reduced to 7:3?
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