Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 7)
7.
How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
Answer: Option
Explanation:
S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.
 C.P. of 1 kg of mixture = Rs. |
 |
100 | x 9.24 |  |
= Rs. 8.40 |
| 110 |
By the rule of allilation, we have:
| C.P. of 1 kg sugar of 1st kind Cost of 1 kg sugar of 2nd kind | ||
| Rs. 9 | Mean Price Rs. 8.40 | Rs. 7 |
| 1.40 | 0.60 | |
Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27
 x = |
|
7 x 27 | |
= 63 kg. |
| 3 |
Discussion:
40 comments Page 4 of 4.
P.s.manikanta said:
1 decade ago
Observe the allegation method which is given as solution. They are mixed in the ratio 1.40:0.60 =14:60. This ratio always remains constant in allegation. They have already given 27kg for sugar costing 7rs/- per kg. The question asked is how many (?) kgs of sugar costing 9rs/- per kg should be mixed. So equate the ratio of weights.
Naimul Samad said:
9 years ago
(x * 9 + 27 * 7) * 110/100 = (x + 27) 9.24.
So, x = 63.
So, x = 63.
Daniel said:
1 decade ago
I have an easy and understandable way I hope for you guys,
Let x be the quantity we are looking for, and qty A be 7/kg while qty B is 9/kg.
Based on unit equivalency;
[(qty A*price of A)+(qty B*price of B)]profit = total amount*9.24.
Thus, (27*7 + x*9)*1.1 = (27 + x)*9.24.
Solve for x, and you will get x = 63.
Let x be the quantity we are looking for, and qty A be 7/kg while qty B is 9/kg.
Based on unit equivalency;
[(qty A*price of A)+(qty B*price of B)]profit = total amount*9.24.
Thus, (27*7 + x*9)*1.1 = (27 + x)*9.24.
Solve for x, and you will get x = 63.
Pushpa said:
1 decade ago
According to rule of allegation the C.P of cheaper qty is kept on the left side and dearer one on the right side but I could see it in other in the solution provided please explain.
Hari Shankar Yadav said:
1 decade ago
I am very satisfied with these answers.
Kjkj tikhir said:
10 years ago
Seriously, this type of question must be for 20 marks question.
Very lengthy answers. But very much appreciated to @Vikatakavee even I didn't cope it.
Very lengthy answers. But very much appreciated to @Vikatakavee even I didn't cope it.
Mehedy said:
10 years ago
Just look,
One value is x & another is 27.
So, we can write like: 1.1 (9x+27*7) = 9.24 (x+27).
Now solve the equation.
One value is x & another is 27.
So, we can write like: 1.1 (9x+27*7) = 9.24 (x+27).
Now solve the equation.
RITIK RANJAN said:
10 years ago
From where does this value 1.40 & 0.60 came from?
And there after ratio?
Please help me out.
Anyone having much better and simpler ideas than this one can openly suggest and guide.
Thank you. Hoping for an early reply.
And there after ratio?
Please help me out.
Anyone having much better and simpler ideas than this one can openly suggest and guide.
Thank you. Hoping for an early reply.
Darpana said:
10 years ago
How is the ratio of 9:7 dropped down to 7:3? Could someone please explain?
Sivaram said:
1 decade ago
Hi Friends,
I can't understand why we take x to b mixed with 27kg of sugar (last step).
Please some one help me out. Thank you.
I can't understand why we take x to b mixed with 27kg of sugar (last step).
Please some one help me out. Thank you.
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