Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 7)
7.
How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
Answer: Option
Explanation:
S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.
 C.P. of 1 kg of mixture = Rs. |
 |
100 | x 9.24 |  |
= Rs. 8.40 |
| 110 |
By the rule of allilation, we have:
| C.P. of 1 kg sugar of 1st kind Cost of 1 kg sugar of 2nd kind | ||
| Rs. 9 | Mean Price Rs. 8.40 | Rs. 7 |
| 1.40 | 0.60 | |
Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27
 x = |
|
7 x 27 | |
= 63 kg. |
| 3 |
Discussion:
42 comments Page 1 of 5.
Mangesh said:
5 years ago
Why use the 100/110? Explain, please.
(10)
Anushka said:
5 years ago
S.P = 9.24
CP = 9.24 * 100/110 = 8.4.
Let the qty of sugar be x;
9x + (27 * 7)/27 + x = 8.4
x= 63kg => answer.
CP = 9.24 * 100/110 = 8.4.
Let the qty of sugar be x;
9x + (27 * 7)/27 + x = 8.4
x= 63kg => answer.
(6)
Avinash Rai said:
1 year ago
@All. Here's my explanation.
Let x kg of 9 Rs. sugar.
Total cost before gain = (9*x + 27*7),
and after gain = (9*x + 27*7) * 1.1 where (10% gain).
This total cost should be equal to 9.24 * (27+x)
By solving, 9.24 * (27+x) = (9*x + 27*7) * 1.1
x = 63.
Let x kg of 9 Rs. sugar.
Total cost before gain = (9*x + 27*7),
and after gain = (9*x + 27*7) * 1.1 where (10% gain).
This total cost should be equal to 9.24 * (27+x)
By solving, 9.24 * (27+x) = (9*x + 27*7) * 1.1
x = 63.
(4)
Namratha said:
5 years ago
Can somebody please explain how 110/100 came, why should we take it like that and what's that?
(4)
S.M. Atik said:
7 years ago
Here, gain of 10% by selling the mixture at 9.24 per kg. So, the cost price per kg in mixture, x+ 10% of x= 9.24,
so, x= 8.4.
Let, x kg of sugar costing 9 per kg mixed in the mixture.
So, 9*x+7*27 = 8.4(x+27),
so, x= 63.
so, x= 8.4.
Let, x kg of sugar costing 9 per kg mixed in the mixture.
So, 9*x+7*27 = 8.4(x+27),
so, x= 63.
(4)
Abhinav said:
7 years ago
According to rule of alligation cheaper should be on the left and the expensive one of the right but why 9 is on the left when it is expensive? Please tell me.
(3)
Andy said:
6 years ago
The first step find the cost price 9.24 * 100/110 = 8.4.
Then equation: (7*27)+(9*X) = 8.4.
Solving X = 63.
Then equation: (7*27)+(9*X) = 8.4.
Solving X = 63.
(2)
Bhumi said:
2 months ago
Formula: SP = (100 + Profit) % * CP.
so, 9.4 = 110 /100 * CP.
CP = 8.4.
Costlier sugar = ₹9/kg
Cheaper sugar = ₹7/kg
Mean price = ₹8.4/kg
Ratio = (9 − 8.4):(8.4 − 7).
Ratio: 3 : 7 :: 27 : x.
Then Ans: x = 63 kg.
so, 9.4 = 110 /100 * CP.
CP = 8.4.
Costlier sugar = ₹9/kg
Cheaper sugar = ₹7/kg
Mean price = ₹8.4/kg
Ratio = (9 − 8.4):(8.4 − 7).
Ratio: 3 : 7 :: 27 : x.
Then Ans: x = 63 kg.
(1)
Thakursaab said:
9 years ago
Let x kg of sugar is mixed with 27kg of sugar.
CP of mixture = x * 9 + 27 * 7,
SP of mixture = (x+27) * 9.24,
Now gain pecentage = ((sp-cp)/cp) * 100,
Put the values ,you will get the answer.
CP of mixture = x * 9 + 27 * 7,
SP of mixture = (x+27) * 9.24,
Now gain pecentage = ((sp-cp)/cp) * 100,
Put the values ,you will get the answer.
(1)
Apoorvuptaa g said:
9 years ago
Please explain. According to rule of allegation the C.P of cheaper qty is kept on the left side and dearer one on the right side but I could see it in other in the solution provided
(1)
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