Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
The maximum stress produced in a bar of tapering section is at
Discussion:
13 comments Page 1 of 2.
Longtsung said:
2 years ago
However, If the type of loading is Self-weight then the maximum stress would be developed at the section where it is fixed.
Shubham Bhuva said:
4 years ago
Absolutely stress is inversely proportional to area.
So, smaller end area is becoming minimum so answer is smaller end.
So, smaller end area is becoming minimum so answer is smaller end.
(4)
RAHUL KUMAR GUPTA said:
4 years ago
As we know that stress is inversely proportional to area. It means area increase then obviously stress decreased. Area of small end is less than larger end. So maximum stress produced at small end.
(1)
ANUTOSH DAS said:
5 years ago
STRESS = FORCE/AREA.
Basar sk said:
6 years ago
As we know, stress inversely proportional to the area. So where the area is minimum stress is maximum. So the answer is a smaller end.
Anomies said:
7 years ago
The bar must be hanging vertically downward.
Hence max stress should act on larger area.
Hence max stress should act on larger area.
Sathish said:
7 years ago
It is Based on force acting.
(1)
Chandra prakash said:
8 years ago
We know that,
Stress = load/area.
I.e. Stress is inversely proportional to the area.
So, the max. Stress is produced in at the smaller end of the bar because their area is less.
Stress = load/area.
I.e. Stress is inversely proportional to the area.
So, the max. Stress is produced in at the smaller end of the bar because their area is less.
G Sunil Reddy said:
1 decade ago
Stress is inversely proportional to area so smaller end take more stress.
Sahib said:
1 decade ago
Stress inversely in relation to the area under consideration.
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