you just add all the X first to get 5X then add numbers to get 30.
Then add 5x+30=50
5X=50-30(shift 30 to right side)
5x=20
X=20/5
X=4
Nandish said:
(Sat, Nov 20, 2010 11:32:15 AM)
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
how 50 come
Prasad Baanu said:
(Sat, Dec 4, 2010 10:28:40 PM)
Hai Nandish..., They have already gave in the question that the sum of ages of those boys are 50:-)
so x + (x+3)+ (x+6)+ (x+9)+(x+12) = 50
Nandan said:
(Wed, Feb 2, 2011 02:33:01 AM)
If 1st child age x then 3year gap for next child so x+3
5 children = 5x
5x+30=50
5x=50-30
5x=20
x=20/5
x=4
so 4 years
Raj said:
(Tue, Feb 15, 2011 09:41:52 AM)
Use arithmetic prog... formula
s=n/2[2a+(n-1)d]
where s=total sum of numbers,n-count the numbers ,d-diff&a-intial no. so they ask intial no i.e a?
s=50,n=5,d=3,a?
50=5/2[2a+12]=>a=4...
Jitu said:
(Sat, Mar 19, 2011 03:59:27 AM)
How can I submitt a question?
Jinju said:
(Sun, Mar 27, 2011 07:51:44 AM)
We can easily understand if the avg is 8 then youngestg should be less thgan 8. Then after we calculate the validity of remaining values.
Stella said:
(Wed, Jun 15, 2011 01:32:17 AM)
Hi cherry, you just see your calculations: x,3x,6x,9x,12x.(wrong)
u have to add x,x+3,x+6,x+9,x+12.(this is the correct format)
now u have to add and get the result ya.
Satheesh said:
(Mon, Jun 27, 2011 02:27:01 AM)
It seems these calculation are merely mathematical wise not logic wise. Whats the relation between X and younger child?
Gkgokulan said:
(Wed, Jul 13, 2011 12:16:05 PM)
Its simple logic frnds 4+7+10+13+16=50.
Then the answer is 4.
Ishu Subham said:
(Thu, Aug 4, 2011 12:12:16 PM)
Let the ages be (x-6), (x-3), (x), (x+3), (x+6).
then sum of ages = 5x
=> 5x = 50
x = 10
youngest = x-6
=4
Sangeetha said:
(Fri, Aug 5, 2011 10:04:45 PM)
Thank you ishu subham, very simple and good logic.
Durgesh said:
(Thu, Aug 11, 2011 07:48:08 PM)
Avg. of age of 5 children = 50/5 = 10
Now there are 5 no. having sum 50 and avg. as 10 so no. can only be
= (10-6),(10=3),(10),(10+3),(10+6)
=4 , 7 ,10 ,13 ,16
Neeraj Dixit said:
(Sat, Sep 17, 2011 04:26:57 PM)
Just go through answer select 4 first will be 4 than 7 than 10, 13, 16 add all five you will get 50.
Since given 5 children=50
let one children be x
given interval 3 each
so x+(x+3)+(x+6)+(x+9)+(x+12)=50
5x+30=50
x=20/5
x=4..
Kumuda said:
(Wed, Sep 28, 2011 12:37:11 PM)
Younger means the person who born at last, then who is the last one, according to problem the person x+12. Submit X value in x+12=16.
Can you please any one clear my doubt ?
Srujan said:
(Wed, Oct 12, 2011 06:31:26 PM)
@kumuda sub x value in all then u will get 4,7,10,13,16.
So among them d least age is 4 i.e younger one.
Sudheer said:
(Mon, Oct 24, 2011 12:00:18 PM)
Let x+(x-3)+(x-6)+(x-9)+(x-12)=50
5x-30=50
5x=80
x=16
is this correct or not?
if it is wrong then explain the reason..
Prince said:
(Wed, Nov 16, 2011 02:23:59 PM)
For all who don't understand here is the simple explanation.
Let the last child ( 5th ) born be x years old,
3 years before the 4th child was born so his age has to be x+3,
now the 3rd child was born 3 years before the 4th child. so the age of 3rd child is 3+3 ie 6+x.
so on..we get
x ( last child ) + x+3 ( a child before x )+ x+6 + x+9 + x+12 =50.
so x+x+x+x+x + 3+6+9+12 =50
5x + 30 =50
5x = 50-30
5x = 20
x = 4.
where x is the youngest child.
Explanation in Hindi: :P
jo last baccha hua uski age x hai...jo usse 3 saal pehle paida hua hoga toh uski age to x se 3 saal badi ho hogi na...so x+3,
so usse 3 saal pehle hua hoga uski age x se 6 saal badi and so on.
Udhay Chandran said:
(Sun, Jan 15, 2012 12:57:45 AM)
Lets assume that the first elder son age is X, then the difference in the age of 3 years among the consecutive child summing to the total age of 50 would be follow.Here (X-3) corresponds to 2nd elder child age and (X-6) corresponds to 3rd elder child age and so on
5x = 20
Age of the youngest child = x = 4 years.