Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 43)
43.
Which one of the following is the common factor of (4743 + 4343) and (4747 + 4347) ?
Answer: Option
Explanation:
When n is odd, (xn + an) is always divisible by (x + a).
Each one of (4743 + 4343) and (4747 + 4347) is divisible by (47 + 43).
Discussion:
17 comments Page 1 of 2.
Maneesh said:
4 years ago
a^3 + b^3 = (a+b) (a2+b2-ab) is odd and we have to plus, i.e. we can divide by a+b.
Whereas, if n is odd and we have minus, a3-b3 formula i.e divide by a-b.
Whereas, if n is odd and we have minus, a3-b3 formula i.e divide by a-b.
Vijaybarath said:
4 years ago
Simply;
a3 + b3 = (a+b) (a2+b2-ab) is odd, i.e we can dived by a+b.
Whereas, if even a3-b3 formula i.e divide by a-b.
a3 + b3 = (a+b) (a2+b2-ab) is odd, i.e we can dived by a+b.
Whereas, if even a3-b3 formula i.e divide by a-b.
Praveen said:
5 years ago
How to divide it? Please explain in detail.
(1)
Navneet said:
7 years ago
Can anyone please explain it, what if the value of n is even? Then what will be the common factor?
(3)
Suyog said:
8 years ago
A number which divides two or more number is called common factor of that number.
Ravi kant said:
9 years ago
When power n is odd then (a+b) divide a^n+b^n.
eg: a^3 + b^3 = (a + b)(a^2 - ab + b^2).
And, if power n is even then it divide a^n-b^n.
eg: a^3 - b^3) = (a - b)(a^2 + ab + b^2).
eg: a^3 + b^3 = (a + b)(a^2 - ab + b^2).
And, if power n is even then it divide a^n-b^n.
eg: a^3 - b^3) = (a - b)(a^2 + ab + b^2).
(2)
Simran said:
9 years ago
Can be solved by cyclicity.
Unit place of 1st number is 0 after addition. Which means it is a factor of 10. Out of options only 43 + 47 = 90 is the factor of 10. So, 43 + 47 is the answer.
Unit place of 1st number is 0 after addition. Which means it is a factor of 10. Out of options only 43 + 47 = 90 is the factor of 10. So, 43 + 47 is the answer.
(2)
Sasikumar said:
9 years ago
Can anyone explain it please?
Naimul said:
9 years ago
(47^43 + 43^43).
= 43^43 (4^43 + 1^43).
Again,
43^47 (4^47 + 1^47).
So, 43^43 * 43^47.
= 43 (43 + 47).
= 43^43 (4^43 + 1^43).
Again,
43^47 (4^47 + 1^47).
So, 43^43 * 43^47.
= 43 (43 + 47).
Akshay said:
10 years ago
When the HCF of two no. is 1, this no. is called common factor.
Ex. 72 = 8*9.
8 = 2^3.
9 = 3^2.
The HCF of 8 & 9 is 1. Hence it makes as common factor.
Ex. 72 = 8*9.
8 = 2^3.
9 = 3^2.
The HCF of 8 & 9 is 1. Hence it makes as common factor.
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