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Aptitude - Logarithm - Discussion

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"We cannot solve our problems with the same thinking we used when we created them."
- Albert Einstein
5. 

If log a + log b = log (a + b), then:
b a

[A]. a + b = 1[B]. a - b = 1
[C]. a = b[D]. a2 - b2 = 1

Answer: Option A

Explanation:

log a + log b = log (a + b)
b a

log (a + b) = log a x b = log 1.
b a

So, a + b = 1.


Charu said: (Fri, Nov 19, 2010 10:19:30 AM)    
 
I can't got it. Please explain it more clearly.

Divya said: (Mon, Jan 10, 2011 12:01:04 PM)    
 
I can't understand your point. Can any one please explain me?

Radhe.. said: (Sun, May 15, 2011 02:43:11 AM)    
 
'+' indicate the multiplication in log.and '-' indicate the division in log....

Siddhu said: (Wed, Aug 10, 2011 10:15:02 AM)    
 
We know that: log a + log b = log (a+b);

Similarly log(a/b) + log(b/a) = log (a/b * b/a);

We get log 1 bcoz all terms will get cancels

and log 1 = 0;

This is about L.H.S. So look at the R.H.S log(a+b) is there and we have to get R.H.S also zero it is possible when we get log 1 = log(a+b) so a+b = 1.

Priya said: (Thu, Sep 1, 2011 09:29:56 PM)    
 
Thanks siddhu.

Raghavendra said: (Fri, Dec 23, 2011 09:47:07 PM)    
 
log(a+b)=log(a/b)+log(b/a)
log(a+b)=l0ga-logb+logb-loga
log(a+b)=0
a+b=10^0
so
a+b=1

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