Aptitude - Logarithm - Discussion
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Read more:"We cannot solve our problems with the same thinking we used when we created them."
- Albert Einstein
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| 5. |
| If log |
a |
+ |
log |
b |
= log (a + b), then: |
| b |
a |
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| [A]. |
a + b = 1 | [B]. |
a - b = 1 | | [C]. |
a = b | [D]. |
a2 - b2 = 1 |
Answer: Option A
Explanation:
| log |
a |
+ log |
b |
= log (a + b) |
| b |
a |
 log (a + b) = log |
 |
a |
x |
b |
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= log 1. |
| b |
a |
So, a + b = 1.
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Charu said:
(Fri, Nov 19, 2010 10:19:30 AM)
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| I can't got it. Please explain it more clearly. |
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Divya said:
(Mon, Jan 10, 2011 12:01:04 PM)
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| I can't understand your point. Can any one please explain me? |
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Radhe.. said:
(Sun, May 15, 2011 02:43:11 AM)
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| '+' indicate the multiplication in log.and '-' indicate the division in log.... |
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Siddhu said:
(Wed, Aug 10, 2011 10:15:02 AM)
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We know that: log a + log b = log (a+b);
Similarly log(a/b) + log(b/a) = log (a/b * b/a);
We get log 1 bcoz all terms will get cancels
and log 1 = 0;
This is about L.H.S. So look at the R.H.S log(a+b) is there and we have to get R.H.S also zero it is possible when we get log 1 = log(a+b) so a+b = 1. |
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Priya said:
(Thu, Sep 1, 2011 09:29:56 PM)
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| Thanks siddhu. |
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Raghavendra said:
(Fri, Dec 23, 2011 09:47:07 PM)
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log(a+b)=log(a/b)+log(b/a)
log(a+b)=l0ga-logb+logb-loga
log(a+b)=0
a+b=10^0
so
a+b=1 |
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