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Aptitude - Logarithm - Discussion

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5. 

If log a + log b = log (a + b), then:
b a

[A].
a + b = 1
[B]. a - b = 1
[C]. a = b[D]. a2 - b2 = 1

Answer: Option A

Explanation:

log a + log b = log (a + b)
b a

log (a + b) = log a x b = log 1.
b a

So, a + b = 1.


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