Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 5)
5.
If log a + log b = log (a + b), then:
b a
a + b = 1
a - b = 1
a = b
a2 - b2 = 1
Answer: Option
Explanation:

log a + log b = log (a + b)
b a

log (a + b) = log a x b = log 1.
b a

So, a + b = 1.

Discussion:
33 comments Page 2 of 4.

Dimpal said:   8 years ago
Not getting this point, please explain clearly.

Preetiranjan panda said:   8 years ago
@Shree.

log{(a+b)/3}=0.5(log a +log b).
=1/2(log a+log b),
=1/2 log a + 1/2 log b,
= log a^1/2 + log b^1/2,
=log (a^1/2 * b^1/2),
=>(a+b)/3 = a^1/2 * b^1/2,
=(ab)^1/2.
=>{(a+b)/3}^2 = ab,
=>(a+b)^2 /3^2= ab,
=>(a+b)^2 /9 = ab,
=>(a+b)^2 = 9ab,
=> a^2 +b^2+2ab = 9ab,
=> a^2+b^2 = 9ab - 2ab,
=> a^2+b^2 = 7ab.
(Proved)

4lick said:   8 years ago
loga + logb = loga/b.

Harsh said:   8 years ago
@Siddharth.

You cancelled out (a-b) from both sides, which is not accepted since a-b=0 and division by 0 is undefined?

Biswas said:   9 years ago
The, log(2+3) = log(2 * 3) should be same in the question 1(b).

Vijaylaxmi said:   9 years ago
According to rules of logarithms.

Log (a+b) =loga*logb.
Log (a/b) =loga-logb.

Siddharth said:   9 years ago
I have a question.

Log a =log b
a = b
a * a = ab
(a * a)- b * b = ab - b *b
(a + b)(a - b) = b(a - b)
a + b = b
But a = b
So
B + b = b
Were is the mistake? Please clarify this.

Amith said:   9 years ago
log (a + b + c) = log a + log b + log c is true only when a + b + c = a * b * c

Eg: 1, 2, 3.

Ravi said:   10 years ago
Formula for log x to base a.

Can anyone help me?

Shree said:   1 decade ago
log x = (1/2) log y = (1/5) log z, the value of x4y3z-2 is?

Can anyone clearly explain step by step please?


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